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Javascript jqueryajax给出500个内部错误_Javascript_Php_Jquery_Ajax - Fatal编程技术网

Javascript jqueryajax给出500个内部错误

Javascript jqueryajax给出500个内部错误,javascript,php,jquery,ajax,Javascript,Php,Jquery,Ajax,我正在尝试使用 jQuery.ajax({ method: "POST", url: "some2.php", data: { data: result } }) .done(function( msg ) { alert( "Data Saved: " + msg );

我正在尝试使用

jQuery.ajax({
                  method: "POST",
                  url: "some2.php",
                  data: { data: result }
                })
                  .done(function( msg ) {
                    alert( "Data Saved: " + msg );
                  });
此代码正确地在
localhost
上发送请求,但在服务器上上载时,会出现错误
500内部错误

实时链接放置在链接处:

我的
some2.php

<?php
function distance($lat1, $lon1, $lat2, $lon2, $unit) {

  $theta = $lon1 - $lon2;
  $dist = sin(deg2rad($lat1)) * sin(deg2rad($lat2)) +  cos(deg2rad($lat1)) * cos(deg2rad($lat2)) * cos(deg2rad($theta));
  $dist = acos($dist);
  $dist = rad2deg($dist);
  $miles = $dist * 60 * 1.1515;
  $unit = strtoupper($unit);

  if ($unit == "K") {
      return ($miles * 1.609344);
  } else if ($unit == "N") {
      return ($miles * 0.8684);
  } else {
      return $miles;
  }
}

$data = $_POST['data'];
$data = explode(",",$data);
print_r($data);
echo "Distance From Khandar Bus Stand : ".distance($data[0], $data[1], 25.992739,76.379046 "K") . " Kilometers<br>";
?>

我缺少的东西请帮助我

请改变

echo "Distance From Khandar Bus Stand : ".distance($data[0], $data[1],  25.992739,76.379046 "K") . " Kilometers<br>";
echo“到坎达尔公共汽车站的距离:.Distance($data[0],$data[1],25.992739,76.379046“K”)。“公里数
”;

echo“到坎达尔公共汽车站的距离:.Distance($data[0],$data[1],25.992739,76.379046,“K”)。“公里数
”;

在单元参数之前调用的
distance
函数中缺少一个逗号。

看起来没有足够的信息来帮助显示完整的代码,包括URL路径。是否尝试忽略
{data:result}
并将其替换为
result
?请检查
some.php
,问题可能就在这里,仅供将来参考,500错误意味着问题在服务器端,所以您需要查看PHP代码,而不是Javascript。
echo "Distance From Khandar Bus Stand : ".distance($data[0], $data[1], 25.992739,76.379046 , "K") . " Kilometers<br>";