PHP/AJAX/Javascript显示网站;年龄“;
我想显示我的网站年龄,但作为一个活生生的结果(像一个反向倒计时通过AJAX等)。现在我有一个PHP脚本,看起来像:PHP/AJAX/Javascript显示网站;年龄“;,javascript,php,ajax,countdown,Javascript,Php,Ajax,Countdown,我想显示我的网站年龄,但作为一个活生生的结果(像一个反向倒计时通过AJAX等)。现在我有一个PHP脚本,看起来像: <?php echo secondsToTime(time()-(1203234532)); # number = timestamp when website was created function secondsToTime($seconds) { $dtF = new DateTime("@0"); $dtT = new DateTime("@$seconds");
<?php
echo secondsToTime(time()-(1203234532)); # number = timestamp when website was created
function secondsToTime($seconds) {
$dtF = new DateTime("@0");
$dtT = new DateTime("@$seconds");
return $dtF->diff($dtT)->format('%a days, %h hours, %i minutes and %s seconds');
}
php>
你所说的“活着”是什么意思,或者可能有帮助。是的,你所说的“活着”是什么意思。该函数有效吗?请查看setTinveral或setTimeout命令@上面jeff的意思是说setInterval
。