Javascript 在重试Ajax场景中，如何消除这种难看的重复代码？

由于

getGamesByPlayerId

的回调调用性质（这恰好是一个Ajax调用），我似乎无法找出如何消除以下重复代码：

// Load the player's games.
gc.api.getGamesByPlayerId(gc.game.player.id, gc.game.player.access_token, function(data) {

    if(data.status_code === 401) {

        // Call may have failed due to being called too fast. Retry...
        gc.api.getGamesByPlayerId(gc.game.player.id, gc.game.player.access_token, function(data) {

            if(data.status_code === 401) {

                // Call may have failed due to being called too fast. Retry...
                gc.api.getGamesByPlayerId(gc.game.player.id, gc.game.player.access_token, function(data) {

                    if(data.status_code === 401) {

                        // Call may have failed due to being called too fast. Retry...
                        gc.api.getGamesByPlayerId(gc.game.player.id, gc.game.player.access_token, function(data) {

                            if(data.status_code === 401) {

                                // OK. It's safe to assume the server is current, and that
                                // we truly are not authorized to do this.
                                alert("You are not authorized.");

                            } else {

                                // Add games to HTML.
                                for( var i = 0; i < data.length; i++ ) {

                                    var html = '<li><a href="?g=' + data[i].id + '">' + data[i].id + '</a></li>';

                                    $('#games').append(html);

                                }

                            }

                        });

                    } else {

                        // Add games to HTML.
                        for( var i = 0; i < data.length; i++ ) {

                            var html = '<li><a href="?g=' + data[i].id + '">' + data[i].id + '</a></li>';

                            $('#games').append(html);

                        }

                    }

                });

            } else {

                // Add games to HTML.
                for( var i = 0; i < data.length; i++ ) {

                    var html = '<li><a href="?g=' + data[i].id + '">' + data[i].id + '</a></li>';

                    $('#games').append(html);

                }

            }

        });

    } else {

        // Add games to HTML.
        for( var i = 0; i < data.length; i++ ) {

            var html = '<li><a href="?g=' + data[i].id + '">' + data[i].id + '</a></li>';

            $('#games').append(html);

        }

    }

});

//加载玩家的游戏。
gc.api.getGamesByPlayerId（gc.game.player.id，gc.game.player.access_令牌，函数（数据）{
如果（data.status_code===401）{
//呼叫可能因呼叫速度过快而失败。请重试。。。
gc.api.getGamesByPlayerId（gc.game.player.id，gc.game.player.access_令牌，函数（数据）{
如果（data.status_code===401）{
//呼叫可能因呼叫速度过快而失败。请重试。。。
gc.api.getGamesByPlayerId（gc.game.player.id，gc.game.player.access_令牌，函数（数据）{
如果（data.status_code===401）{
//呼叫可能因呼叫速度过快而失败。请重试。。。
gc.api.getGamesByPlayerId（gc.game.player.id，gc.game.player.access_令牌，函数（数据）{
如果（data.status_code===401）{
//好的，可以安全地假设服务器是最新的，并且
//我们确实无权这样做。
警惕（“您未被授权”）；
}否则{
//将游戏添加到HTML。
对于（变量i=0；i

---

通常情况下，我会考虑使用for循环，但这不会起作用，因为我不想快速连续地发出Ajax调用。我希望只有在前面的调用失败时才会触发重试。

忽略需要连续多次发出相同请求的情况，您可能可以使用递归函数来实现这一点。例如，类似于：

loadPlayerGames(4);

function loadPlayerGames(triesLeft) {
    gc.api.getGamesByPlayerId(gc.game.player.id, gc.game.player.access_token, function(data) {
        if(data.status_code !== 401) {
            // Add games to HTML.
            for( var i = 0; i < data.length; i++ ) {
                var html = '<li><a href="?g=' + data[i].id + '">' + data[i].id + '</a></li>';
                $('#games').append(html);
            }
        } else if(triesLeft <= 0) {
            // OK. It's safe to assume the server is current, and that
            // we truly are not authorized to do this.
            alert("You are not authorized.");
        } else {
            // Call may have failed due to being called too fast. Retry...
            loadPlayerGames(triesLeft - 1);
        }
    });
}

loadPlayerGames（4）；
函数loadPlayerGames（特里斯勒夫特）{
gc.api.getGamesByPlayerId（gc.game.player.id，gc.game.player.access_令牌，函数（数据）{
如果（data.status_code！==401）{
//将游戏添加到HTML。
对于（变量i=0；i}否则，如果（triesLeft忽略需要连续多次发出相同请求的情况，则可以使用递归函数来完成此操作。例如：

loadPlayerGames(4);

function loadPlayerGames(triesLeft) {
    gc.api.getGamesByPlayerId(gc.game.player.id, gc.game.player.access_token, function(data) {
        if(data.status_code !== 401) {
            // Add games to HTML.
            for( var i = 0; i < data.length; i++ ) {
                var html = '<li><a href="?g=' + data[i].id + '">' + data[i].id + '</a></li>';
                $('#games').append(html);
            }
        } else if(triesLeft <= 0) {
            // OK. It's safe to assume the server is current, and that
            // we truly are not authorized to do this.
            alert("You are not authorized.");
        } else {
            // Call may have failed due to being called too fast. Retry...
            loadPlayerGames(triesLeft - 1);
        }
    });
}

loadPlayerGames（4）；
函数loadPlayerGames（特里斯勒夫特）{
gc.api.getGamesByPlayerId（gc.game.player.id，gc.game.player.access_令牌，函数（数据）{
如果（data.status_code！==401）{
//将游戏添加到HTML。
对于（变量i=0；i}否则如果（特里斯里夫特）我为什么没想到呢？谢谢！我为什么没想到呢？谢谢！