Javascript Amcharts-如何删除网格线但保留基本x轴和y轴
如何仅删除网格线并在AMCHART4中保留x轴和y轴基线。我正在将Amcharts与Vuejs一起使用。下面是图表组件的代码Javascript Amcharts-如何删除网格线但保留基本x轴和y轴,javascript,amcharts,Javascript,Amcharts,如何仅删除网格线并在AMCHART4中保留x轴和y轴基线。我正在将Amcharts与Vuejs一起使用。下面是图表组件的代码 <template> <b-card> <div class="d-flex align-items-center justify-content-between"> <h5>Real Time</h5> </div>
<template>
<b-card>
<div class="d-flex align-items-center justify-content-between">
<h5>Real Time</h5>
</div>
<div class="real-time-graph mt-4" ref="chartdiv"></div>
</b-card>
</template>
<script>
import * as am4core from "@amcharts/amcharts4/core";
import * as am4charts from "@amcharts/amcharts4/charts";
import am4themes_animated from "@amcharts/amcharts4/themes/animated";
am4core.useTheme(am4themes_animated);
export default {
name: "main-details",
mounted() {
let chart = am4core.create(this.$refs.chartdiv, am4charts.XYChart);
chart.data = [{
"date": "2020-01-01",
"value1": 180,
}, {
"date": "2020-01-08",
"value1": 300,
}, {
"date": "2020-01-15",
"value1": 160,
}, {
"date": "2020-01-22",
"value1": 650,
}, {
"date": "2020-01-29",
"value1": 220,
}, {
"date": "2020-02-05",
"value1": 440,
}, {
"date": "2020-02-12",
"value1": 550,
}, {
"date": "2020-02-19",
"value1": 290,
}, {
"date": "2020-02-26",
"value1": 440,
}, {
"date": "2020-03-04",
"value1": 150,
}, {
"date": "2020-03-11",
"value1": 430,
}];
// Set input format for the dates
chart.dateFormatter.inputDateFormat = "yyyy-MM-dd";
chart.numberFormatter.numberFormat = '#,###w';
// Create axes
var dateAxis = chart.xAxes.push(new am4charts.DateAxis());
dateAxis.renderer.minGridDistance = 50;
dateAxis.renderer.grid.template.disabled = true;
dateAxis.renderer.line.disabled = false;
dateAxis.renderer.ticks.template.disabled = true;
dateAxis.renderer.labels.template.fill = am4core.color("#C3CDDD");
var valueAxis = chart.yAxes.push(new am4charts.ValueAxis());
valueAxis.renderer.grid.template.disabled = true;
valueAxis.renderer.labels.template.fill = am4core.color("#C3CDDD");
// Create series
var series1 = chart.series.push(new am4charts.StepLineSeries());
series1.dataFields.valueY = "value1";
series1.dataFields.dateX = "date";
series1.strokeWidth = 2;
series1.stroke = "#3AB7FD";
series1.fillOpacity = 1;
var gradient1 = new am4core.LinearGradient();
gradient1.addColor(chart.colors.getIndex(0), 0.2);
gradient1.addColor(chart.colors.getIndex(0), 0);
gradient1.rotation = 90;
series1.fill = gradient1;
}
}
</script>
这是上述代码的输出图。我需要同时显示x和y基准轴,并且只显示删除的网格线。您可以将strokeOpacity设置为非零值以显示轴线:
dateAxis.renderer.line.strokeOpacity = 1;
valueAxis.renderer.line.strokeOpacity = 1;
演示:
let chart=am4core.create(“chartdiv”,am4charts.XYChart);
chart.data=[{
“日期”:“2020-01-01”,
“价值1”:180,
}, {
“日期”:“2020-01-08”,
“价值1”:300,
}, {
“日期”:“2020-01-15”,
“价值1”:160,
}, {
“日期”:“2020-01-22”,
“价值1”:650,
}, {
“日期”:“2020-01-29”,
“价值1”:220,
}, {
“日期”:“2020-02-05”,
“价值1”:440,
}, {
“日期”:“2020-02-12”,
“价值1”:550,
}, {
“日期”:“2020-02-19”,
“价值1”:290,
}, {
“日期”:“2020-02-26”,
“价值1”:440,
}, {
“日期”:“2020-03-04”,
“价值1”:150,
}, {
“日期”:“2020-03-11”,
“价值1”:430,
}];
//设置日期的输入格式
chart.dateFormatter.inputDateFormat=“yyyy-MM-dd”;
chart.numberFormatter.numberFormat='#,####w';
//创建轴
var dateAxis=chart.xAxes.push(新的am4charts.dateAxis());
dateAxis.renderer.minGridDistance=50;
dateAxis.renderer.grid.template.disabled=true;
dateAxis.renderer.ticks.template.disabled=true;
dateAxis.renderer.labels.template.fill=am4core.color(“#C3CDDD”);
dateAxis.renderer.line.strokeOpacity=1;
var valueAxis=chart.yAxes.push(新的am4charts.valueAxis());
valueAxis.renderer.grid.template.disabled=true;
valueAxis.renderer.labels.template.fill=am4core.color(“#C3CDDD”);
valueAxis.renderer.line.strokeOpacity=1;
//创建系列
var series1=chart.series.push(新的am4charts.StepLineSeries());
series1.dataFields.valueY=“value1”;
series1.dataFields.dateX=“日期”;
系列1.strokeWidth=2;
序列1.stroke=“#3AB7FD”;
series1.fillOpacity=1;
var gradient1=新的am4core.LinearGradient();
gradient1.addColor(chart.colors.getIndex(0),0.2);
gradient1.addColor(chart.colors.getIndex(0),0);
梯度1.旋转=90;
系列1.填充=渐变1代码>
dateAxis.renderer.line.strokeOpacity = 1;
valueAxis.renderer.line.strokeOpacity = 1;