将多维数组从javascript发送到PHP

嗨，我正在努力解决这个问题

我有一个javascript数组，通过$POST发送到PHP，使用：

jsonScrutineeringArray = JSON.stringify(scrutineeringArray);

在PHP中，我会：

$jsonScrutineeringArray = $_REQUEST["jsonScrutineeringArray"];
$tempData = html_entity_decode($jsonScrutineeringArray);
$jsonScrutineeringArray2 = json_decode($tempData);
echo json_encode($jsonScrutineeringArray2);
for ($ii = 0; $ii < count($jsonScrutineeringArray2); ++$ii) {
    echo 'driverID ='.$jsonScrutineeringArray2['driverID'][$ii];
}

所以我假设我在PHP中有一个格式正确的数组

但是，我无法使用以下变量回显单个字段：

echo 'driverID ='.$jsonScrutineeringArray2['driverID'][$ii];

我错过了什么

谢谢

更新。如果我使用var_dump（$jsonscrutingeringarray2）

我得到：

array(3) {
[0]=>
object(stdClass)#2 (20) {
["ID"]=>
int(1)
["driverID"]=>
string(1) "1"
["event"]=>
string(0) ""
["race"]=>
string(0) ""
["FRTagID"]=>
string(0) ""
["FRDepth"]=>
string(0) ""
["FRNotes"]=>
string(0) ""
["FRFail"]=>
string(0) ""
["FLTagID"]=>
string(0) ""
["FLDepth"]=>
string(0) ""
["FLNotes"]=>
string(0) ""
["FLFail"]=>
string(0) ""
["RRTagID"]=>
string(0) ""
["RRDepth"]=>
string(0) ""
["RRNotes"]=>
string(0) ""
["RRFail"]=>
string(0) ""
["RLTagID"]=>
string(0) ""
["RLDepth"]=>
string(0) ""
["RLNotes"]=>
string(0) ""
["RLFail"]=>
string(0) ""
}
[1]=>
object(stdClass)#3 (20) {
["ID"]=>
int(1)
["driverID"]=>
string(1) "1"
["event"]=>
string(21) "Silverstone 21/2/2015"
["race"]=>
string(5) "Race2"
["FRTagID"]=>
string(2) "11"
["FRDepth"]=>
string(0) ""
["FRNotes"]=>
string(0) ""
["FRFail"]=>
string(4) "Fail"
["FLTagID"]=>
string(3) "111"
["FLDepth"]=>
string(0) ""
["FLNotes"]=>
string(0) ""
["FLFail"]=>
string(4) "Fail"
["RRTagID"]=>
string(4) "1111"
["RRDepth"]=>
string(0) ""
["RRNotes"]=>
string(0) ""
["RRFail"]=>
string(4) "Fail"
["RLTagID"]=>
string(5) "11111"
["RLDepth"]=>
string(0) ""
["RLNotes"]=>
string(0) ""
["RLFail"]=>
string(4) "Fail"
}
[2]=>
object(stdClass)#4 (20) {
["ID"]=>
int(2)
["driverID"]=>
string(1) "2"
["event"]=>
string(21) "Silverstone 12/3/2015"
["race"]=>
string(5) "Race3"
["FRTagID"]=>
string(2) "22"
["FRDepth"]=>
string(0) ""
["FRNotes"]=>
string(0) ""
["FRFail"]=>
string(4) "Fail"
["FLTagID"]=>
string(3) "222"
["FLDepth"]=>
string(0) ""
["FLNotes"]=>
string(0) ""
["FLFail"]=>
string(4) "Fail"
["RRTagID"]=>
string(4) "2222"
["RRDepth"]=>
string(0) ""
["RRNotes"]=>
string(0) ""
["RRFail"]=>
string(4) "Fail"
["RLTagID"]=>
string(5) "22222"
["RLDepth"]=>
string(0) ""
["RLNotes"]=>
string(0) ""
["RLFail"]=>
string(4) "Fail"
}
}

那么，我该如何循环使用它呢？

而不是

echo 'driverID ='.$jsonScrutineeringArray2['driverID'][$ii];

试试这个：

echo 'driverID ='.$jsonScrutineeringArray2[$ii]->driverID;

你可以试试

foreach ($jsonScrutineeringArray2 as $jsonScrutineering) {
    echo 'Driver ID = ' . $jsonScrutineering->driverID;
}

json\u decode（$json，$assoc=false）

默认将JS哈希解析为标准对象。

$jsonscrutingeringarray2[$ii]>driverID

设置第二个参数以请求PHP关联数组。

$jsonscrutingeringarray2[$ii]['driverID']

您在钥匙顺序上也犯了错误。

echo'driverID=。$jsonscrutingeringarray2[$ii]['driverID']

而不是

echo'driverID='。$jsonscrutingeringarray2['driverID'][$ii]
尝试使用
$jsonscrutineringarray2[$ii]['driverID']]
尝试简化它，在数据上使用foreach循环，并在每个步骤中转储变量web nomad$jsonscrutineringarray2[$ii]['driverID']不起作用这工作正常回音'driverID='。$jsonscrutineringarray2[$ii]>driverID；
foreach ($jsonScrutineeringArray2 as $jsonScrutineering) {
    echo 'Driver ID = ' . $jsonScrutineering->driverID;
}