Javascript 将Firebase.key()推送到对象
我有一个相当简单的Javascript 将Firebase.key()推送到对象,javascript,firebase,angularfire,Javascript,Firebase,Angularfire,我有一个相当简单的createService函数,可以将数据发送到我的Firebase。运行时,它将my$scope.serviceTitle推送到名为服务的对象,并将my$scope.providerTitle推送到名为提供者的对象 main.js $scope.createService = function() { var newService = { title: $scope.serviceTitle }; var newProvider = { title: $scope.p
createService
函数,可以将数据发送到我的Firebase。运行时,它将my$scope.serviceTitle
推送到名为服务的对象,并将my$scope.providerTitle
推送到名为提供者的对象
main.js
$scope.createService = function() {
var newService = { title: $scope.serviceTitle };
var newProvider = { title: $scope.providerTitle };
var servicePromise = ServiceService.add(newService);
var providerPromise = ProviderService.add(newProvider);
};
angular.module('outcomesApp').service('ServiceService', function(FBURL, $firebase) {
var serviceRef = new Firebase(FBURL).child('services');
var fireService = $firebase(serviceRef).$asArray();
return {
add: function addService(service) {
return fireService.$add(service);
}
};
});
ServiceService.js
$scope.createService = function() {
var newService = { title: $scope.serviceTitle };
var newProvider = { title: $scope.providerTitle };
var servicePromise = ServiceService.add(newService);
var providerPromise = ProviderService.add(newProvider);
};
angular.module('outcomesApp').service('ServiceService', function(FBURL, $firebase) {
var serviceRef = new Firebase(FBURL).child('services');
var fireService = $firebase(serviceRef).$asArray();
return {
add: function addService(service) {
return fireService.$add(service);
}
};
});
我的数据最终如下所示:
{
"services": {
"-JgDvQz_opBMdULBPySG": {
"title": "Hernia Repair"
}
},
"providers": {
"-JgDp4zieowSM-ymfDHR": {
"title": "The Whittington Hospital",
}
}
}
当我运行createService()
函数时,我想推送第三个对象,该函数名为service\u at_provider
,其中service
的值为我刚才推送的服务.key()
,而provider
的值为providerkey()
。这可能有助于理解我试图实现的目标:
{
"services": {
"-JgDvQz_opBMdULBPySG": {
"title": "Hernia Repair"
}
},
"providers": {
"-JgDp4zieowSM-ymfDHR": {
"title": "The Whittington Hospital",
}
},
"service_at_provider": {
"-JgDvQzYxtYGp7JspWYr": {
"service": "-JgDvQz_opBMdULBPySG", // matches the 'newService' just pushed
"provider": "-JgDp4zieowSM-ymfDHR" // matches the 'newProvider' just pushed
}
}
}
由于$add
,因此servicespromise
变量返回一个承诺。但我不知道如何返回键()
,并在同一推送过程中将其传递给一个名为服务提供者的新对象
这可能吗?解析返回到新firebase引用的承诺。您可以在createService中执行以下操作
$q.all([servicePromise, providerPromise]).then(function(refs) {
var serviceRef = refs[0];
var providerRef = refs[1];
// service key
serviceRef.key();
// provider key
providerRef.key();
// Use that data to add to your service_at_provider array
});