Warning: file_get_contents(/data/phpspider/zhask/data//catemap/9/javascript/412.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
如何在javascript中获取xml parentNode属性值_Javascript_Jquery - Fatal编程技术网

如何在javascript中获取xml parentNode属性值

如何在javascript中获取xml parentNode属性值,javascript,jquery,Javascript,Jquery,我有一个如下所示的xml var myXml = new XmlDOM(false); var xmlval = "<ParentNode Symbol="$"><Row book = "test" price ="80"/> </ParentNode>"; myXml.LoadXML(xmlval); 如何从上述xml中获取符号值 我尝试了myXml.getAttribute等 请帮帮我 var xmlval = '<ParentNode Sym

我有一个如下所示的xml

var myXml = new XmlDOM(false);
var xmlval = "<ParentNode Symbol="$"><Row book = "test" price ="80"/>   </ParentNode>";
myXml.LoadXML(xmlval);
如何从上述xml中获取符号值

我尝试了myXml.getAttribute等

请帮帮我

var xmlval = '<ParentNode Symbol="$"><Row book = "test" price ="80"/>   </ParentNode>';
var symbol = $(xmlval).attr('Symbol');

您不需要在xmlval中转义引号吗?是的,我已经在JSFIDLE中修复了它,但是忘记了更新示例。谢谢