Javascript 从Mysql查询中获取5列及其值并转换为PHP

经过几次尝试，我无法找到一个简单而优雅的解决方案

本质上，我想要一种方法来获取从这个查询中获取的5个字段，并将它们分配给PHP变量，然后再分配给最近的Javascript变量

<?php
    include_once('connect.php');
    $result = mysqli_query($conn, " SELECT DISTINCT IPdestport as destport,COUNT(*) as count FROM PACKETSFORIP GROUP BY destport ORDER BY count DESC LIMIT 5;");  

    while($row[] = mysqli_fetch_array($result))
    {
        $destport1 = $row[1][ 'destport' ];
        $destport2 = $row[2]['destport'];
        $destport3 = $row[3]['destport'];
        $destport4 = $row[4]['destport'];
        $destport5 = $row[5]['destport'];
        $count1 = $row[1]['count'];            
        $count2 = $row[2]['count'];
        $count3 = $row[3]['count'];
        $count4 = $row[4]['count'];
        $count5 = $row[5]['count']; 

    }
    ?>

                        var obj = <?php echo $portarray; ?>;

                    for(var i= 0; i < obj.length; i++) {
                    var json = obj[i];
                    destport = json.destport;
                    numberofpackets = json.count;


                    destport = destport.toString();
                    numberofpackets= parseInt(numberofpackets);

下面是更多的代码，我将最终如何将这些PHP变量转换为Javascript变量，以便将它们处理为google图表

var destport1 = "<?php echo $destport1 ?>";
var destport2 = "<?php echo $destport2 ?>";
var destport3 = "<?php echo $destport3 ?>";
var destport4 = "<?php echo $destport4 ?>";
var destport5 = "<?php echo $destport5 ?>";
var count1 = "<?php echo $count1 ?>";
var count2 = "<?php echo $count2 ?>";
var count3 = "<?php echo $count3 ?>";
var count4 = "<?php echo $count4 ?>";
var count5 = "<?php echo $count5 ?>";

var destport1=“”；
var destport2=“”；
var destport3=“”；
var destport4=“”；
var destport5=“”；
var count1=“”；
var count2=“”；
var count3=“”；
var count4=“”；
var count5=“”；

---

任何帮助都将不胜感激。谢谢。

使用数组可以节省大量重复代码

要简化第一步（将它们分配给PHP变量），只需将结果集转换为数组：

$destPorts = mysqli_fetch_all($result);

$destPorts

将包含结果集中的所有行。如果要访问第二行的“计数”列，请使用：

$destPorts[1]['count']

$destPorts[3]['destport']

destPorts[1].count

destPorts[3].destport

或要访问第四行的“destport”列，请使用：

$destPorts[1]['count']

$destPorts[3]['destport']

destPorts[1].count

destPorts[3].destport

由于这些值存储在$destPorts数组中，因此无需将它们转换为单独的变量

<?php
    include_once('connect.php');
    $result = mysqli_query($conn, " SELECT DISTINCT IPdestport as destport,COUNT(*) as count FROM PACKETSFORIP GROUP BY destport ORDER BY count DESC LIMIT 5;");  

    while($row[] = mysqli_fetch_array($result))
    {
        $destport1 = $row[1][ 'destport' ];
        $destport2 = $row[2]['destport'];
        $destport3 = $row[3]['destport'];
        $destport4 = $row[4]['destport'];
        $destport5 = $row[5]['destport'];
        $count1 = $row[1]['count'];            
        $count2 = $row[2]['count'];
        $count3 = $row[3]['count'];
        $count4 = $row[4]['count'];
        $count5 = $row[5]['count']; 

    }
    ?>

                        var obj = <?php echo $portarray; ?>;

                    for(var i= 0; i < obj.length; i++) {
                    var json = obj[i];
                    destport = json.destport;
                    numberofpackets = json.count;


                    destport = destport.toString();
                    numberofpackets= parseInt(numberofpackets);

您可以在JavaScript中执行类似的操作。不是创建单独的变量，而是：

或要访问第四行的“destport”列，请使用：

$destPorts[1]['count']

$destPorts[3]['destport']

destPorts[1].count

destPorts[3].destport

---

当您将结果行存储在数组和对象中而不是简单的数字索引变量中时，您的代码重复性更小，更灵活。您不再需要知道数据库中有多少个结果；您只需在阵列或对象上循环并访问所有数据。

对于将来搜索此项的任何人，这是我最终使用的解决方案。在我以前编写的web应用程序中找到它

       <?php
                     include_once('connect.php');
      $result = mysqli_query($conn, " SELECT DISTINCT IPdestport as destport,COUNT(*) as count FROM PACKETSFORIP GROUP BY destport ORDER BY count DESC LIMIT 5;");  
          $portsarray = Array();
          $countarray = Array();
            while($row = mysqli_fetch_array($result))
              {
        $portarray[] = array('destport'=>$row['destport'], 'count'=>$row['count']);
            echo $row['count'];
              }

          $portarray = json_encode($portarray);


    ?>

上面的代码获取每个端口以及发送到该端口的数据包的数量，这些数据后来被转换成javascript并输入到google图表中，但我将只展示获取PHP数组并将其中包含的变量放入javascript变量的部分

<?php
    include_once('connect.php');
    $result = mysqli_query($conn, " SELECT DISTINCT IPdestport as destport,COUNT(*) as count FROM PACKETSFORIP GROUP BY destport ORDER BY count DESC LIMIT 5;");  

    while($row[] = mysqli_fetch_array($result))
    {
        $destport1 = $row[1][ 'destport' ];
        $destport2 = $row[2]['destport'];
        $destport3 = $row[3]['destport'];
        $destport4 = $row[4]['destport'];
        $destport5 = $row[5]['destport'];
        $count1 = $row[1]['count'];            
        $count2 = $row[2]['count'];
        $count3 = $row[3]['count'];
        $count4 = $row[4]['count'];
        $count5 = $row[5]['count']; 

    }
    ?>

                        var obj = <?php echo $portarray; ?>;

                    for(var i= 0; i < obj.length; i++) {
                    var json = obj[i];
                    destport = json.destport;
                    numberofpackets = json.count;


                    destport = destport.toString();
                    numberofpackets= parseInt(numberofpackets);

var obj=；
对于（变量i=0；i

如果代码的第一部分有效，只需将第二部分放在

标记中，它就可以完成任务（虽然不漂亮，但可以正常工作）