Javascript 如何访问<；路径>；在SVG文档中

我正在创建几个可单击的地图，但在试图找到如何访问路径标记以便使地图中的所有不同县都可单击时失败。（SVG文件非常复杂…这是结构，我无法更改它-它会自动为所有不同的状态生成）：

---

看起来您刚刚将s从getElementsByTagName中删除了

<svg width="932.25827pt" height="569.25354pt" viewBox="0 0 932.25827 569.25354" enable-background="new 0 0 932.25827 569.25354"
version="1.1" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" >
<g id="Layers">
    <g id="Ohio_Counties">
        <clipPath id="SVG_CP_1">
            <path d="M0,569.25354L0,0L932.25827,0L932.25827,569.25354L0,569.25354z"/>
        </clipPath>
        <path clip-path="url(#SVG_CP_1)" fill="none" stroke="#4E4E4E" stroke-width="0.48003" stroke-miterlimit="10" stroke-linecap="round" stroke-linejoin="round" d="
    M374.18483,441.14215L375.38491,440.90214L375.62493,440.90214L376.58499,440.66213L376.82501,440.66213L377.54505,440.42212
            L378.02508,440.42212L378.2651,440.42212L378.74513,440.42212L379.46518,440.66213L381.14529,440.66213L381.38531,440.66213L
            381.62532,440.66213L382.10536,440.66213L382.8254,440.66213L384.50551,440.90214L384.74553,440.90214L386.18563,440.90214L386.42564,441.38217
            L386.42564,441.62218L386.42564,441.86219L386.66566,441.86219L386.90567,441.86219L386.90567,442.1022L386.90567,442.34221L"/>
       </path>   
    </g>
</g>

/* There are about 87 more paths in the file... this is just a part of one.*/

function changeState(newState){
    nS = newState.replace(/\s/g, '');

    try {      
        var map = 'mapLayers/AEP'+nS+'Counties.svg';
            $("#contentCounties").empty();
            var currentCountyMap = $('#contentCounties').svg({loadURL: loc, onLoad: addClickEvents(this)});

        } catch(err){
           alert("the map " + currentCountyMap + " does not exist");
    }
}


function addClickEvents(){
    // this is where I want to put the code to 
    // add click events to the individual paths.
    // Whether it's running a loop or using a jquery selector
    // I'm fine with either.

    // This is, in theory, what I think I want - but alas, it is wrong:
    var svg=document.getElementByTagName("path");
    alert(svg);
}