Javascript 分解多个函数

也许是个愚蠢的问题，但是：

我如何分解这种代码

  var rsc = this.checkRsc(path)
  if (rsc)

基本上，我想在使用任何方法之前检查一个东西是否为null

checkRsc: function(path) {
  var rsc = manager.get(path);
  if (rsc != undefined)
    return rsc;
  else
    return null;
},
func1: function(path) {
  var rsc = this.checkRsc(path)
  if (rsc)
    this.doStuff(rsc);
},
func2: function(path) {
  var rsc = this.checkRsc(path)
  if (rsc)
    this.doStuffAnotherStuff(rsc);
},
func3: function(path) {
  var wave = this.checkRsc(path)
  if (wave)
    this.andAgain(wave);
},
func4: function(path) {
  var rsc = this.checkRsc(path)
  if (rsc)
    this.AndsomethingElse(rsc);
}

---

也传递要执行的函数，如下所示

checkRsc: function(path, func, context) {
  var rsc = manager.get(path);
  if (rsc != undefined)
    return func.call(context, rsc);
  else
    return null;
},

this.checkRsc(path, this.doStuff, this)
...
this.checkRsc(path, this.doStuffAnotherStuff, this)
...
this.checkRsc(path, this.andAgain, this)

    return [this.nested.again func obj (without context)].call(this.nested, rsc);

然后像这样调用它

checkRsc: function(path, func, context) {
  var rsc = manager.get(path);
  if (rsc != undefined)
    return func.call(context, rsc);
  else
    return null;
},

this.checkRsc(path, this.doStuff, this)
...
this.checkRsc(path, this.doStuffAnotherStuff, this)
...
this.checkRsc(path, this.andAgain, this)

    return [this.nested.again func obj (without context)].call(this.nested, rsc);

---

注意：我建议也传递上下文，因为如果您想在嵌套对象中执行函数，这会很方便。比如说,

this.checkRsc(path, this.nested.again, this.nested)

现在,

我会像这样工作

checkRsc: function(path, func, context) {
  var rsc = manager.get(path);
  if (rsc != undefined)
    return func.call(context, rsc);
  else
    return null;
},

this.checkRsc(path, this.doStuff, this)
...
this.checkRsc(path, this.doStuffAnotherStuff, this)
...
this.checkRsc(path, this.andAgain, this)

    return [this.nested.again func obj (without context)].call(this.nested, rsc);

---

if（rsc！=未定义）返回rsc；否则返回null

==>

返回src | nully嗯，我没有精确说明func1、fun2、func3等中的代码。。我想重构^^^将方法名传递给
func
，创建
rsc
，检查其存在性，并使用括号表示法调用该方法：
this[method\u name]（rsc）需要时。这样你就只需要一个函数。好的函数也会检查这个