Javascript 试着做煎饼
我正在做一个有趣的任务,我在搜索过程中发现了这个任务,以进行健壮的验证,下面是我的验证代码Javascript 试着做煎饼,javascript,Javascript,我正在做一个有趣的任务,我在搜索过程中发现了这个任务,以进行健壮的验证,下面是我的验证代码 Pan = “1234567890-=[]{}%^*+_\|~<>€$¥•.,?!/()£&@“ # this is my list that I’m going to check an input against Valid = False while Valid ==False: Valid = True Forename=input(“Ple
Pan = “1234567890-=[]{}%^*+_\|~<>€$¥•.,?!/()£&@“ # this is my list that I’m going to check an input against
Valid = False
while Valid ==False:
Valid = True
Forename=input(“Please enter name”)
For i in range (0,len(pan)):
if input[i] in pan == False:
Valid == False
信息是
TypeError:“内置函数”或“方法”对象不可下标
事先抱歉,我有点不知所措请注意:
- 应使用
not
应该是Valid==False
,因为您正在设置一个变量Valid=False
应以小写字母开头的
pan = “1234567890-=[]{}%^*+_\|~<>€$¥•.,?!/()£&@“ # this is my list that I’m going to check an input against
valid = False
while valid == False:
valid = True
forename = input("Please enter name")
for i in range (0,len(pan)):
if input[i] not in pan:
valid = False
您发布的代码中有几个问题。首先,您要求输入名称由Pan中的字符组成——名称通常按字母顺序排列,因此我担心您的逻辑颠倒了。然而
pan = “1234567890-=[]{}%^*+_\|~<>€$¥•.,?!/()£&@“ # valid characters
forename = input(“Please enter name”)
valid = False
while not valid:
valid = True # input is good until we get a bad value
for i in range (0, len(forename)):
if forename[i] not in pan:
valid = False
break
谢谢,伙计,但我不明白char是什么,请你解释一下char只是一个代表单个字符的变量。请注意,如果在中间两行中交换PAN和No.1,这同样适用。谢谢,我对计算还是相当新的,但是谢谢你们帮助我摆脱了ErgLad的帮助。我们都是新来的。这就是为什么我给了你一个使用你当前工具集的解决方案,然后又给了你一个使用一些高级工具的解决方案。不过,没有什么比看到你的代码工作更好的了。当你得到一个解决方案时,请记着投票选出有用的东西,并接受你最喜欢的答案(即使你必须自己写),因此,堆栈溢出可以正确地归档问题。
name = input("Please enter a name")
valid = True
for char in pan:
if char in name:
valid = False
break
pan = “1234567890-=[]{}%^*+_\|~<>€$¥•.,?!/()£&@“ # valid characters
forename = input(“Please enter name”)
valid = False
while not valid:
valid = True # input is good until we get a bad value
for i in range (0, len(forename)):
if forename[i] not in pan:
valid = False
break
forename = "INVALID NAME"
# Are all the name's characters found in pan?
while not all(char in pan for char in forename):
forename = input(“Please enter name”)