Javascript 按json数组中的键/值进行筛选
这是我的代码,我只想显示有“协助”作为标记的项目,而没有其他项目。我真的不知道该怎么做Javascript 按json数组中的键/值进行筛选,javascript,jquery,Javascript,Jquery,这是我的代码,我只想显示有“协助”作为标记的项目,而没有其他项目。我真的不知道该怎么做 function displayall(newid){ $.ajax({ url: "https://cubber.zendesk.com/api/v2/users/"+newid+"/tickets/requested.json", type: 'GET', cors: true, dataType: 'json', contentType:'
function displayall(newid){
$.ajax({
url: "https://cubber.zendesk.com/api/v2/users/"+newid+"/tickets/requested.json",
type: 'GET',
cors: true,
dataType: 'json',
contentType:'application/json',
secure: true,
beforeSend: function (xhr) {
xhr.setRequestHeader ("Authorization", "Basic " + btoa(""));
},
success: function (data){
var sortbydate = data.tickets.sort(function(a,b){ return new Date(b.created_at)- new Date(a.created_at); });
for (i = 0; i < data.tickets.length; i++) {
var myticket = data.tickets[i];
var mydate = data.tickets[i].created_at;
var created = moment(mydate).format("MM-DD-YY");
var mytitle = data.tickets[i].subject;
var description = data.tickets[i].description;
var status = data.tickets[i].status;
var ticketid = data.tickets[i].id;
var tag = data.tickets[i].tags[0];
$("#mylist").append('<li class="row col-md-12 listing" id="newlist" value="'+ticketid+'" onclick="ticketcontent('+ticketid+","+newid+')">'+ '<span class="class_'+status+' otherClasses">' + status + '</span>'+'<div class="identifiant fixed col-md-2">'+" #"+ ticketid +'</div>'+'<div class="identifiant col-md-2">'+tag+'</div>'+'<div class="identifiant col-md-4">'+mytitle +'</div>'+'<div class="identifiant datefixed col-md-2">'+created+'</div>'+'</li>');
}
}
})
}
函数displayall(newid){
$.ajax({
url:“https://cubber.zendesk.com/api/v2/users/“+newid+”/tickets/requested.json”,
键入:“GET”,
科尔斯:是的,
数据类型:“json”,
contentType:'application/json',
安全:是的,
发送前:函数(xhr){
xhr.setRequestHeader(“授权”、“基本”+btoa(“”);
},
成功:功能(数据){
var sortbydate=data.tickets.sort(函数(a,b){返回新日期(b.created_at)–新日期(a.created_at);});
对于(i=0;i“+”+“+status+”+“+”+“+ticketid+”+“+tag+”+”+“+mytitle+”+“+”+”+“+created+”+”);
}
}
})
}
如果我使用console.log(data.ticket[i]),我得到的是:
尝试使用
data.tickets.filter()
:
尝试使用
data.tickets.filter()
:
您需要的是:
var filteredTickets = data.tickets.filter(function(ticket) {
return ticket.tags.indexOf('assistance') >= 0;
});
您需要的是:
var filteredTickets = data.tickets.filter(function(ticket) {
return ticket.tags.indexOf('assistance') >= 0;
});