Javascript 从链接的axios请求合并两个阵列
我将一组axios get请求链接到API的不同端点,并尝试从数据创建一个类似这样的数组(简化): 在其中一个请求中,我检索数组中每个人的姓名和id,如下所示:Javascript 从链接的axios请求合并两个阵列,javascript,arrays,object,axios,chain,Javascript,Arrays,Object,Axios,Chain,我将一组axios get请求链接到API的不同端点,并尝试从数据创建一个类似这样的数组(简化): 在其中一个请求中,我检索数组中每个人的姓名和id,如下所示: [ { name: "John", id: 1 }, { name: "Anna", id: 2 }, ] let peopleArray = []; axios.get('api/' + 'getPeopleArray').then(pe
[
{
name: "John",
id: 1
},
{
name: "Anna",
id: 2
},
]
let peopleArray = [];
axios.get('api/' + 'getPeopleArray').then(people => {
peopleArray = people;
people.forEach((person, index) => {
axios.get('api/' + 'getGender?id='.concat(person.id.toString()))
.then(gender => {
peopleArray[index].gender = gender;
});
});
});
现在,我只需要通过在两个单独的请求中将每个人的id发送到端点来获取他们的性别
我花了几个小时试图用push()和then()在顶部构造数组,但我就是做不好
我该怎么做?
<html>
<head>
<script src="https://unpkg.com/axios/dist/axios.min.js"></script>
</head>
<body>
<script>
getConnectionStatusData();
async function getConnectionStatusData() {
let serviceDomains = await axios.get('http://api.ntjp.se/coop/api/v1/serviceDomains.json', {
params: {
namespace: "crm:scheduling"
}
});
serviceDomainId = serviceDomains.data[0].id;
let connectionPoints = await axios.get('http://api.ntjp.se/coop/api/v1/connectionPoints.json', {
params: {
platform: "NTJP",
environment: "PROD"
}
});
connectionPointId = connectionPoints.data[0].id;
let logicalAddresss = await axios.get('http://api.ntjp.se/coop/api/v1/logicalAddresss.json', {
params: {
logicalAdress: "SE2321000016-167N",
serviceConsumerHSAId: "SE2321000016-92V4",
connectionPointId: connectionPointId
}
});
logicalAddressId = logicalAddresss.data[0].id;
let serviceConsumers = await axios.get('http://api.ntjp.se/coop/api/v1/serviceConsumers.json', {
params: {
connectionPointId: connectionPointId,
logicalAddressId: logicalAddressId
}
});
consumer = serviceConsumers.data.filter(obj => {
return obj.hsaId === "SE2321000016-92V4"
});
serviceConsumerId = consumer[0].id;
let cooperations = await axios.get('http://api.ntjp.se/coop/api/v1/cooperations.json', {
params: {
connectionPointId: connectionPointId,
logicalAddressId: logicalAddressId,
serviceDomainId: serviceDomainId,
serviceConsumerId: serviceConsumerId,
include: "serviceContract"
}
});
for(var idx in cooperations.data) {
var data = async () => { return await axios.get('http://api.ntjp.se/coop/api/v1/serviceProducers.json', {
params: {
connectionPointId: connectionPointId,
logicalAddressId: logicalAddressId,
serviceDomainId: serviceDomainId,
serviceConsumerId: serviceConsumerId,
serviceContractId: cooperations.data[idx].serviceContract.id
}
}) }
cooperations.data[idx].producerDescription = data.description;
cooperations.data[idx].producerHSAId = data.hsaId;
}
console.log(cooperations.data);
}
</script>
</body>
我正在链接axios请求,如下所示:
axios.get('api/' + endpoint1]).then(response => {
axios.get('api/' + endpoint2).then(response => {
axios.get('api/' + endpoint3).then(response => {
// and so on...
});
});
});
更新1:
我觉得我没有正确地解释这个问题。这就是我的代码现在的样子,从上一个承诺开始。如何更改它以使数组位于问题的顶部
.then(response => {
people= response.data; // Array of people including their name id (not their gender though)
for (var key in people) {
var person = {};
person["name"] = people[key].node.name;
person["id"] = people[key].node.id;
finalArray.push(person);
axios.get('api/' + endpoint3, { // Endpoint for getting a persons gender from id
params: {
personId: person.id
}
}).then(response => {
// I don't know what to do here...
});
}
console.log(finalArray); // Gives me an array of objects without "gender".
});
更新2:
非常感谢你的回答
我结合了您的一些解决方案,这就是我现在真正的代码的外观。未发送到的请求为什么?
<html>
<head>
<script src="https://unpkg.com/axios/dist/axios.min.js"></script>
</head>
<body>
<script>
getConnectionStatusData();
async function getConnectionStatusData() {
let serviceDomains = await axios.get('http://api.ntjp.se/coop/api/v1/serviceDomains.json', {
params: {
namespace: "crm:scheduling"
}
});
serviceDomainId = serviceDomains.data[0].id;
let connectionPoints = await axios.get('http://api.ntjp.se/coop/api/v1/connectionPoints.json', {
params: {
platform: "NTJP",
environment: "PROD"
}
});
connectionPointId = connectionPoints.data[0].id;
let logicalAddresss = await axios.get('http://api.ntjp.se/coop/api/v1/logicalAddresss.json', {
params: {
logicalAdress: "SE2321000016-167N",
serviceConsumerHSAId: "SE2321000016-92V4",
connectionPointId: connectionPointId
}
});
logicalAddressId = logicalAddresss.data[0].id;
let serviceConsumers = await axios.get('http://api.ntjp.se/coop/api/v1/serviceConsumers.json', {
params: {
connectionPointId: connectionPointId,
logicalAddressId: logicalAddressId
}
});
consumer = serviceConsumers.data.filter(obj => {
return obj.hsaId === "SE2321000016-92V4"
});
serviceConsumerId = consumer[0].id;
let cooperations = await axios.get('http://api.ntjp.se/coop/api/v1/cooperations.json', {
params: {
connectionPointId: connectionPointId,
logicalAddressId: logicalAddressId,
serviceDomainId: serviceDomainId,
serviceConsumerId: serviceConsumerId,
include: "serviceContract"
}
});
for(var idx in cooperations.data) {
var data = async () => { return await axios.get('http://api.ntjp.se/coop/api/v1/serviceProducers.json', {
params: {
connectionPointId: connectionPointId,
logicalAddressId: logicalAddressId,
serviceDomainId: serviceDomainId,
serviceConsumerId: serviceConsumerId,
serviceContractId: cooperations.data[idx].serviceContract.id
}
}) }
cooperations.data[idx].producerDescription = data.description;
cooperations.data[idx].producerHSAId = data.hsaId;
}
console.log(cooperations.data);
}
</script>
</body>
我也不想在调用之前将整个对象保存在cooperations响应数组中。我只想从每个对象保存两个特定的键/值对。这两个键/值对都位于每个响应对象中名为“serviceContract”的对象中如何保存它们?
<html>
<head>
<script src="https://unpkg.com/axios/dist/axios.min.js"></script>
</head>
<body>
<script>
getConnectionStatusData();
async function getConnectionStatusData() {
let serviceDomains = await axios.get('http://api.ntjp.se/coop/api/v1/serviceDomains.json', {
params: {
namespace: "crm:scheduling"
}
});
serviceDomainId = serviceDomains.data[0].id;
let connectionPoints = await axios.get('http://api.ntjp.se/coop/api/v1/connectionPoints.json', {
params: {
platform: "NTJP",
environment: "PROD"
}
});
connectionPointId = connectionPoints.data[0].id;
let logicalAddresss = await axios.get('http://api.ntjp.se/coop/api/v1/logicalAddresss.json', {
params: {
logicalAdress: "SE2321000016-167N",
serviceConsumerHSAId: "SE2321000016-92V4",
connectionPointId: connectionPointId
}
});
logicalAddressId = logicalAddresss.data[0].id;
let serviceConsumers = await axios.get('http://api.ntjp.se/coop/api/v1/serviceConsumers.json', {
params: {
connectionPointId: connectionPointId,
logicalAddressId: logicalAddressId
}
});
consumer = serviceConsumers.data.filter(obj => {
return obj.hsaId === "SE2321000016-92V4"
});
serviceConsumerId = consumer[0].id;
let cooperations = await axios.get('http://api.ntjp.se/coop/api/v1/cooperations.json', {
params: {
connectionPointId: connectionPointId,
logicalAddressId: logicalAddressId,
serviceDomainId: serviceDomainId,
serviceConsumerId: serviceConsumerId,
include: "serviceContract"
}
});
for(var idx in cooperations.data) {
var data = async () => { return await axios.get('http://api.ntjp.se/coop/api/v1/serviceProducers.json', {
params: {
connectionPointId: connectionPointId,
logicalAddressId: logicalAddressId,
serviceDomainId: serviceDomainId,
serviceConsumerId: serviceConsumerId,
serviceContractId: cooperations.data[idx].serviceContract.id
}
}) }
cooperations.data[idx].producerDescription = data.description;
cooperations.data[idx].producerHSAId = data.hsaId;
}
console.log(cooperations.data);
}
</script>
</body>
我不太确定你的具体问题。但假设您的意思是有两个端点,第一个是返回对象数组的端点(我们称之为
'getPeopleArray'
):
第二个端点返回给定id
的gender
(让我们用一个参数id
将其称为'getGender'
),.push
将不会为您执行此任务
您的问题可以通过以下方式解决:
[
{
name: "John",
id: 1
},
{
name: "Anna",
id: 2
},
]
let peopleArray = [];
axios.get('api/' + 'getPeopleArray').then(people => {
peopleArray = people;
people.forEach((person, index) => {
axios.get('api/' + 'getGender?id='.concat(person.id.toString()))
.then(gender => {
peopleArray[index].gender = gender;
});
});
});
首先,保存第一个请求返回的数组,然后必须循环该数组中的每个对象,使用[].forEach(callbackfn)
的index
参数从第二个端点获取并分配其性别。只要在所有请求完成期间或之前没有使用peopleArray
进行操作,索引就会正确
更新2:
针对您在评论中提出的问题“为什么.推送不起作用?”,如果您想使用.push
结束算法,并且不使用跟踪索引,我决定采用另一种方法
let peopleArray = [];
axios.get('api/' + 'getPeopleArray').then(people => {
people.forEach((person) => {
axios.get('api/' + 'getGender?id='.concat(person.id.toString()))
.then(gender => {
peopleArray.push({id: person.id, name: person.name, gender, gender});
});
});
});
通过这种方式,只有在获取对象的性别时,才会将对象推送到集合peopleArray
。这还将消除使用.map
(如注释中所建议)仅存储您希望保留的单个对象的属性的情况,因为您在第行peopleArray.push上推送了一个新的结构化对象({id:person.id,name:person.name,gender,gender})
我不喜欢阅读连锁承诺,而是喜欢使用async/await
。您可以先获取列表,然后使用地图循环该列表,并请求每个姓名的性别。请记住,在继续之前,您必须等待映射中的所有承诺都得到解决
const axios = require('axios');
async function getPeople() {
let firstResult = await axios.get('api/path/endpoint1');
// firstResult = [{name: "John", id: 1}, {name: "Anna", id: 2}]
let updatedResult = firstResult.map(async item => {
let people = await axios.get('api/path/endpoint2' + item.name); // or however your endpoint is designed
// people = {name: "John", id: 1, gender: male}
item.gender = people.gender;
return item;
});
// updatedResult = undefined
Promise.all(updatedResult)
.then(finalResult => console.log(finalResult));
// [{name: "John", id: 1, gender: male}, {name: "Anna", id: 2, gender: female}]
}
您可以使用async/awaits并将gender
键重新分配给第一个端点数据
var users;
axios.get('api/' + endpoint1]).then(response => {
users = response; // assume all user id list
for(var idx in users) {
var data = async () => { return await axios.get('api/' + users[idx].id) } //get gender api by user id
users[idx].gender = data.gender; //create gender key value
}
console.log(users);
});
只需将endpoint1修改为包含性别!它将保存编码行和服务器请求:)@デビット: API不是我的。看看你有没有想过使用wait
?这可能会清理你的代码第二个请求的结果是什么?哇!我试试看。但是在每次调用之后,在执行下一次调用之前,我必须对检索到的数据运行一些过滤函数等。如下所示:var John=response.data.filter(obj=>{return obj.someretriedvalue===someStoredValue})如何实现它?在进行下一步之前,您可以在每次调用后执行任何您想要的操作。所以你可以简单地在中间加上一行,没问题:)为什么Promise.all是必需的?等待不是意味着在接下一个电话之前等待吗?如果我有10个电话,我是否需要将他们所有的名字(让我们)都放在Promise.all()中?如果你wait
在map
中,它将返回需要解决的承诺。将名称放入map函数中。因此,您创建了一个name=[“Alex”,“Anna”]数组,并使用该数组调用map names.map(//这里的异步函数)。完成后,您使用名称作为参数,如下所示:Promise.all(name).then(result=>console.log(result))代码>好的,下面是我对真实数据的了解:由于API在http上,所以无法运行fiddle,但您至少可以看到代码。注意结尾的评论。这就是我被困的地方。你能帮帮我吗?我想JavaScriptMy bad中没有等待
关键字!谢谢你的提醒!请看我原来帖子的更新2。谢谢!推不起作用的原因是什么?另外,来自getPeopleArray的响应包含一组我不想保存的数据。我只想保存姓名和身份证。它还能用吗?谢谢!请查看我的原始帖子的更新2。@RawlandHustle是的,您实际上可以使用.map
保存数组中每个对象的特定属性。因此,您不必只在peopleArray
中保存人员(查看给定的示例peopleArray=people;
),而必须使用.map。示例:peopleArray=people.map(p=>{id:p.id,name:p.name})
@RawlandHustle,.push
执行它应该执行的操作,即向数组中添加一个元素。在您的情况下,您不希望将性别推送到id名称对象的数组中。您将获得类似于[{id:1,name:'abc'},{id:2,name:'def'},'female']
的内容,而不是添加gender
属性