Javascript 为什么这个文本效果不起作用?
我正在尝试从修改脚本以处理多个跨度 我已经试过了,但它似乎用相同的文本覆盖了两个跨距Javascript 为什么这个文本效果不起作用?,javascript,Javascript,我正在尝试从修改脚本以处理多个跨度 我已经试过了,但它似乎用相同的文本覆盖了两个跨距 <html> <head> <script> var got; var chars; function change(decSpan,encSpan) { var randstring = ""; var rslength = chars.length - got.length; var decrypted = document.getElementBy
<html>
<head>
<script>
var got;
var chars;
function change(decSpan,encSpan)
{
var randstring = "";
var rslength = chars.length - got.length;
var decrypted = document.getElementById(decSpan);
var encrypted = document.getElementById(encSpan);
for(var x=0;x<rslength;x++)
{
i = Math.floor(Math.random() * chars.length);
randstring += chars.charAt(i);
}
if(randstring.charAt(0) == chars.charAt(got.length))
{
got += randstring.charAt(0);
decrypted.innerHTML = got;
}
else
{
encrypted.innerHTML = randstring;
}
if(chars.length > got.length)
{
setTimeout("change('"+decSpan+"','"+encSpan+"')", 10);
}
else
{
encrypted.innerHTML = "";
}
}
function startdecrypt()
{
var decodeSpans = ["decoded","decoded2"];
var encodeSpans = ["encoded","encoded2"];
for(var z in decodeSpans)
{
decSpan = decodeSpans[z];
encSpan = encodeSpans[z];
var decrypted = document.getElementById(decSpan);
var encrypted = document.getElementById(encSpan);
chars = decrypted.innerHTML;
decrypted.innerHTML = "";
got = "";
setTimeout("change('"+decSpan+"','"+encSpan+"')", 10);
}
}
</script>
</head>
<body bgcolor="#FFFFFF" text="#000000">
<input type="button" value="go" onClick="javascript:startdecrypt()"><br>
<span id="decoded">Test1</span><span id="encoded"></span><br>
<span id="decoded2">Test2</span><span id="encoded2"></span>
</body>
</html>
var-got;
var-chars;
功能更改(decSpan、encSpan)
{
var randstring=“”;
var rslength=chars.length-got.length;
var decrypted=document.getElementById(decSpan);
var encrypted=document.getElementById(encSpan);
对于(变量x=0;x得到的长度)
{
设置超时(“更改(“+decSpan+”,“+encSpan+”)”,10);
}
其他的
{
encrypted.innerHTML=“”;
}
}
函数startdecrypt()
{
var decodespands=[“decoded”,“decoded2”];
var encodespan=[“encoded”,“encoded2”];
for(变量z,单位为)
{
decSpan=decodeSpans[z];
encSpan=encodespan[z];
var decrypted=document.getElementById(decSpan);
var encrypted=document.getElementById(encSpan);
chars=decrypted.innerHTML;
decrypted.innerHTML=“”;
得到“”;
设置超时(“更改(“+decSpan+”,“+encSpan+”)”,10);
}
}
测试1
测试2
问题在于该脚本使用全局javascript变量:chars
和got
在startdecrypt
中设置,稍后在change
函数中使用。因此,循环的下一次迭代将覆盖以前设置的值
最好的解决方案可能是将它们包含在change
函数的js调用中,就像您对ids所做的那样
另外,请确保将所有js变量声明为本地变量,以避免此类副作用:
var get=”“
我承认没有通读您的全部代码,但您似乎无意中关闭了Javascript,如本例所示:
或者,正如Nikita所说,全局变量,当在change()
函数中引用它时,它就构成了一个闭包。请注意,for的内的var
不会改变任何内容。Javascript没有块作用域
请注意,在循环中使用var
,或在函数顶部声明var x
具有相同的效果。你可能想考虑使用<代码>让代替:
闭包很难理解,尤其是意外的闭包。Ender在上述链接上的回答包含了关于它们如何工作的有用链接。如果我理解正确,这应该可以满足您的要求:
var decodeSpans = ["decoded", "decoded2"];
var encodeSpans = ["encoded","encoded2"];
function encoder(decSpan, encSpan){
this.encSpan = encSpan;
this.decSpan = decSpan;
var got = "";
var chars = decSpan.innerHTML;
decSpan.innerHTML = "";
return (function(){
var randstring = "";
var rslength = chars.length - got.length;
for(var x=0;x<rslength;x++){
i = Math.floor(Math.random() * chars.length);
randstring += chars.charAt(i);
}
if(randstring.charAt(0) == chars.charAt(got.length)){
got += randstring.charAt(0);
decSpan.innerHTML = got;
}else{
encSpan.innerHTML = randstring;
}
if(chars.length > got.length){
decSpan.innerHTML = chars;
encSpan.innerHTML = "";
}else{
encSpan.innerHTML = "";
}
})();
}
function startdecrypt(){
for(var z = 0; z < decodeSpans.length; z++){
decSpan = decodeSpans[z];
encSpan = encodeSpans[z];
var decrypted = document.getElementById(decSpan);
var encrypted = document.getElementById(encSpan);
encoder(decrypted, encrypted);
}
}
var decodeSpans=[“decoded”,“decoded2”];
var encodespan=[“encoded”,“encoded2”];
功能编码器(decSpan、encSpan){
this.encSpan=encSpan;
this.decSpan=decSpan;
var-got=“”;
var chars=decSpan.innerHTML;
decSpan.innerHTML=“”;
返回(函数(){
var randstring=“”;
var rslength=chars.length-got.length;
对于(变量x=0;x得到的长度){
decSpan.innerHTML=chars;
encSpan.innerHTML=“”;
}否则{
encSpan.innerHTML=“”;
}
})();
}
函数startdecrypt(){
对于(var z=0;z
我只是在两天前才正确地阅读了闭包,所以我仍然试图将其全部放在上下文中,所以对于这个解决方案的一些(建设性的)反馈将受到了解这些事情的人的欢迎:)单击按钮时,文本会随机更改,但仍然使用原始文本中的所有字符。如果这是你想要的,它对我很有用。“不工作”是什么意思?