如何在TypeScript/JavaScript中定义多个命名属性

在“myItemA”对象的“sorting”属性中，我希望允许定义多个灵活命名的属性，例如“viewOrder”、“execOrder”、“persistOrder”。。。 然后像这样使用：

   myItemA.sorting.viewOrder = 3;
   myItemA.sorting.execOrder = 7;
   etc.

export abstract class ItemA {
    constructor(
      public id: string,
      public name: string,
                       // (this is may not be correct - how to correct it ?)
      public sorting?: [ {[name: string]: number} ],
      ...

export const myItemA: ItemA = 
  {
    id: 'A1',
    name: 'A1',
                       // (compiler complains here - how to correct it ?)
    sorting: [ {'viewOrder': 0}, {'execOrder': 0}, {etc.} ],
    ...
  }

我正在尝试ItemA的定义和属性排序，如下所示：

   myItemA.sorting.viewOrder = 3;
   myItemA.sorting.execOrder = 7;
   etc.

export abstract class ItemA {
    constructor(
      public id: string,
      public name: string,
                       // (this is may not be correct - how to correct it ?)
      public sorting?: [ {[name: string]: number} ],
      ...

export const myItemA: ItemA = 
  {
    id: 'A1',
    name: 'A1',
                       // (compiler complains here - how to correct it ?)
    sorting: [ {'viewOrder': 0}, {'execOrder': 0}, {etc.} ],
    ...
  }

然后创建如下对象：

   myItemA.sorting.viewOrder = 3;
   myItemA.sorting.execOrder = 7;
   etc.

export abstract class ItemA {
    constructor(
      public id: string,
      public name: string,
                       // (this is may not be correct - how to correct it ?)
      public sorting?: [ {[name: string]: number} ],
      ...

export const myItemA: ItemA = 
  {
    id: 'A1',
    name: 'A1',
                       // (compiler complains here - how to correct it ?)
    sorting: [ {'viewOrder': 0}, {'execOrder': 0}, {etc.} ],
    ...
  }

---

构造函数中的语法应如下所示：

公共排序？：{[name:string]：number}

或：

公共排序？：记录

声明变量时如下所示：

export const myItemA:ItemA={
...
排序：{'viewOrder'：0，'execOrder'：0}，
};

您可以尝试

{[name:string]：number；}[]

或

数组

。为什么不干脆

公共排序？：{[name:string]：number；}

？这基本上可以像您的第一个示例一样，将一对多属性添加到

排序中<代码>排序：{viewOrder:0，execOrder:0，…}

是的，为什么我要用[]使它复杂化？。谢谢。