Javascript 如何使用Promise.all在Angular9中进行两个api调用?
我使用Javascript 如何使用Promise.all在Angular9中进行两个api调用?,javascript,node.js,angular,promise,angular-promise,Javascript,Node.js,Angular,Promise,Angular Promise,我使用Promise进行api调用。所有如下所示: Promise.all(this.hostName.slice(0, this.Id.length).map((hostName) => { return this.serviceC.status(hostName) .then(res => { return new Promise((resolve, reject) => {
Promise进行api调用。所有如下所示:
Promise.all(this.hostName.slice(0, this.Id.length).map((hostName) => {
return this.serviceC.status(hostName)
.then(res => {
return new Promise((resolve, reject) => {
const oretry: ORInterface = {
oQid: res.rows[0].qid,
reason: this.reason
};
this.serviceB.retry(oretry).subscribe(resolve);
});
});
}))
.then(() => {
this.dialog.close();
})
.catch(err => {
console.log(err);
});
const sretry: SDInterface = {
hostName,
Id: this.Id.slice(0, this.Id.length),
reason: this.reason
};
上面的代码运行良好。
现在,我想在成功完成this.serviceB.retry(oretry)
后进行另一个api调用。
第二个api是this.serviceB.createDbEntry(sentry)
并且sentry
如下所示:
Promise.all(this.hostName.slice(0, this.Id.length).map((hostName) => {
return this.serviceC.status(hostName)
.then(res => {
return new Promise((resolve, reject) => {
const oretry: ORInterface = {
oQid: res.rows[0].qid,
reason: this.reason
};
this.serviceB.retry(oretry).subscribe(resolve);
});
});
}))
.then(() => {
this.dialog.close();
})
.catch(err => {
console.log(err);
});
const sretry: SDInterface = {
hostName,
Id: this.Id.slice(0, this.Id.length),
reason: this.reason
};
而且,我正在做的事情如下
Promise.all(this.hostName.slice(0, this.Id.length).map((hostName) => {
return this.serviceC.status(hostName)
.then(res => {
return new Promise((resolve, reject) => {
const oretry: ORInterface = {
oQid: res.rows[0].qid,
reason: this.reason
};
const sretry: SDInterface = {
hostName,
Id: this.Id.slice(0, this.Id.length),
reason: this.reason
};
this.serviceB.retry(oretry).subscribe(resolve);
this.serviceB.createDbEntry(sentry).subscribe(resolve);
});
});
}))
.then(() => {
this.dialog.close();
})
.catch(err => {
console.log(err);
});
上述代码给出了一个错误:
error: "SequelizeValidationError: string violation: Id cannot be an array or an object"
看起来它没有为每个Id
承诺调用第二个api。所有在数组中获取输入并在数组中给出响应
创建两个函数,每个函数的异步逻辑返回一个承诺
说出funcA和funcB,然后使用下面的命令并行调用它们
Promise.all([funcA(this.hostName), funcB(this.id)])
.then(respones => {
console.log(responses[0]); //return value for funcA
console.log(responses[1]); //return value for funcB
})
.catch(err => console.log(err));
我假设你的函数逻辑是正确的,我只是从你的问题中复制粘贴并给出它们的结构
const funcA = (hostName) => {
hostName.slice(0, this.Id.length).map((hostName) => {
return this.serviceC.status(hostName)
.then(res => {
return new Promise((resolve, reject) => {
const oretry: ORInterface = {
oQid: res.rows[0].qid,
reason: this.reason
};
this.serviceB.retry(oretry).subscribe(resolve);
});
});
});
}
const funcB = (Id) => {
Id.slice(0, this.Id.length).map(id => {
return new Promise((resolve, reject) => {
const sretry: SDInterface = {
hostName,
Id: id,
reason: this.reason
};
this.serviceB.createDbEntry(sentry).subscribe(resolve);
});
})
}
您可能需要查看一个forkJoin
import { Observable, forkJoin } from 'rxjs';
然后
ngOnInit() {
let one = this.http.get('some/api/1') //some observable;
let two = this.http.get('some/api/2') // another observable;
forkJoin([one, tow]).subscribe(response => {
// results[0] is our one call
// results[1] is our second call
let var1 = response[1];
let var2 = response[0];
}/*, error => { in case error handler } */);
}
再次使用Promise.all()
不是更好吗
Promise.all(this.hostName.slice(0, this.Id.length).map((hostName) => {
return this.serviceC.status(hostName)
.then(res => {
return new Promise((resolve, reject) => {
const oretry: ORInterface = {
oQid: res.rows[0].qid,
reason: this.reason
};
this.serviceB.retry(oretry).subscribe(resolve);
});
})
.then(() => {
return Promise.all(this.Id.slice(0, this.Id.length).map(id => {
return new Promise((resolve, reject) => {
const sretry: SDInterface = {
hostName,
Id: id,
reason: this.reason
};
this.serviceB.createDbEntry(sentry).subscribe(resolve);
});
})
});
}))
.then(() => {
this.dialog.close();
})
.catch(err => {
console.log(err);
});
使用toPromise()
将使代码更加简洁
Promise.all(this.hostName.slice(0, this.Id.length).map((hostName) => {
return this.serviceC.status(hostName)
.then(res => {
const oretry: ORInterface = {
oQid: res.rows[0].qid,
reason: this.reason
};
return this.serviceB.retry(oretry).toPromise();
})
.then(() => {
return Promise.all(this.Id.slice(0, this.Id.length).map(id => {
const sretry: SDInterface = {
hostName,
Id: id,
reason: this.reason
};
this.serviceB.createDbEntry(sentry).toPromise();
})
});
}))
.then(() => {
this.dialog.close();
})
.catch(err => {
console.log(err);
});
使用CombineTest,在角度上,我们使用RxJs而不是承诺
combineLatest(
[this.http.get('call1'), this.http.get('call2')]
).subscribe(([result1, result2]) => {
// do stuff with result1 and result2
});
请更新您的答案,并演示如何在funcA
中使用this.hostName.slice(0,this.Id.length)
和在funcB
中使用this.Id.slice(0,this.Id.length)
?funcB
引发错误TS2663:找不到名称“hostName”。您的意思是实例成员“this.hostName”吗?
如何将hostName
从funcA
传递到funcB
?funcB
仍在抛出错误TS2304:找不到name”hostName
我正在尝试使用toPromise()
但出现错误TSLint:缺少分号(分号)
通过再添加一个括号,分号错误消失了…this.serviceB.createDbEntry(sentry.toPromise();})代码>请注意,现在这个.serviceB.createDbEntry(sentry).toPromise()代码>运行了两次而不是一次。你能检查一下吗?我依赖于promise
。我可以使用上面的答案中的toPromise()
使其工作。唯一的问题是this.serviceB.createDbEntry(sentry.toPromise()代码>运行两次而不是一次。你能检查一下吗?