Javascript Symfony-FormType-动态选择

我有一个包含1个EntityType字段的表单，该表单必须包含第二个EntityType字段的选项，该字段未映射到第一个实体中，如下所示：

ServicePlaceType.php：

public function buildForm(FormBuilderInterface $builder, array $options)
{
    $builder
        ->add('placetype', EntityType::class, array(
            "class" => "AppBundle:PlaceType",
            "choice_label" => "place",
            "mapped" => false
        ))
        ->add('idplace', EntityType::class, array(
            "class" => "AppBundle:Place",
            "choice_label" => "place"
        ))
        ->add('...');

桌子

+---------+--------------+---------------+-----------+
| Service | ServicePlace |     Place     | PlaceType |
+---------+--------------+---------------+-----------+
|         | id           |               |           |
+---------+--------------+---------------+-----------+
|         | idplace >    | < id          |           |
+---------+--------------+---------------+-----------+
| id >    | < idservice  | idPlaceType > | < id      |
+---------+--------------+---------------+-----------+
| service |              | place         | placetype |
+---------+--------------+---------------+-----------+

有人知道如何获取这些数据吗？或者如何通过另一种方式动态筛选选项

谢谢你的帮助

您可以使用更简单一点的库：

首先，我们将用于渲染位置类型id的生成器稍微更改为使用choice\u attr选项：

接下来，在模板中：

{# ... #}

{{ form(form) }}

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>
<script>
    // when the 1st <select> was changed, then update the 2nd 
    // from current value and data-type option attribute.
    $(document).on('change', '#form_placetype', function () {
        var $idplace = $('#form_idplace'),
            // current value
            placetype = $(this).val(),
            // select available options from current value
            $available = $idplace.find('option[data-type="' + placetype + '"]');

        // deselect when the 1st <select> has changed.
        $idplace.val('');
        // hide no available options from current value
        $idplace.find('option').not($available).hide();
        // show available options from current value
        $available.show();
    });

    // Update 2nd <select> on page load.
    $('#form_placetype').trigger('change');
</script>

---

请尝试使用“选择标签”=>“placeType”，谢谢您的建议。我考虑过了，但我需要标签是地名！成功了吗现在就看吧：x。伊塞鲁托的解决方案对我来说是个好办法选择是解决方案！我现在想拥抱你：

$builder
    ->add('placetype', EntityType::class, array(
        "class" => "AppBundle:PlaceType",
        "mapped" => false
    ))
    ->add('idplace', EntityType::class, array(
        "class" => "AppBundle:Place",
        'choice_attr' => function ($place) {
            // output: <option data-type="...">...</option>
            return array('data-type' => $place->getPlaceType()->getId());
        },
    ))

{# ... #}

{{ form(form) }}

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>
<script>
    // when the 1st <select> was changed, then update the 2nd 
    // from current value and data-type option attribute.
    $(document).on('change', '#form_placetype', function () {
        var $idplace = $('#form_idplace'),
            // current value
            placetype = $(this).val(),
            // select available options from current value
            $available = $idplace.find('option[data-type="' + placetype + '"]');

        // deselect when the 1st <select> has changed.
        $idplace.val('');
        // hide no available options from current value
        $idplace.find('option').not($available).hide();
        // show available options from current value
        $available.show();
    });

    // Update 2nd <select> on page load.
    $('#form_placetype').trigger('change');
</script>