Javascript 使用Bluebird链接结果
在解析链中,每个元素的输入都是前一个元素的解析值(除非它不是函数),是否有任何方便的方法 我试图将以下逻辑链接到一个方法中:Javascript 使用Bluebird链接结果,javascript,bluebird,Javascript,Bluebird,在解析链中,每个元素的输入都是前一个元素的解析值(除非它不是函数),是否有任何方便的方法 我试图将以下逻辑链接到一个方法中: function getClient() { // resolves with the client } function getClientProduct(client) { // resolves with the product } var response = {}; // global response object; function p
function getClient() {
// resolves with the client
}
function getClientProduct(client) {
// resolves with the product
}
var response = {}; // global response object;
function prepareResponse(product) {
// prepares global response object, resolves with `undefined`
}
promise.someMethod(getClient, getClientProduct, prepareResponse, response)
.then(data=> {
// data = the response object;
});
我希望避免写以下内容(如果可能):
那些箭头函数没有意义。你可以做得很简单
getClient().then(getClientProduct).then(prepareResponse).…
没有方便的方法可以进一步缩短,我想你不想考虑
[getClient, getClientProduct, prepareResponse].reduce((p,fn)=>p.then(fn), Promise.resolve())
对于最后一个,您可以使用。这些箭头函数没有意义。你可以做得很简单
getClient().then(getClientProduct).then(prepareResponse).…
没有方便的方法可以进一步缩短,我想你不想考虑
[getClient, getClientProduct, prepareResponse].reduce((p,fn)=>p.then(fn), Promise.resolve())
对于最后一种方法,您可以使用。您实际上并不需要一种方便的方法。你可以这样写:
function getClient() {
// resolves with the client
}
function getClientProduct(client) {
// resolves with the product
}
var response = {}; // global response object;
function prepareResponse(product) {
// prepares global response object, resolves with `undefined`
}
getClient()
.then(getClientProduct)
.then(prepareResponse)
.return(response);
你真的不需要一个方便的方法。你可以这样写:
function getClient() {
// resolves with the client
}
function getClientProduct(client) {
// resolves with the product
}
var response = {}; // global response object;
function prepareResponse(product) {
// prepares global response object, resolves with `undefined`
}
getClient()
.then(getClientProduct)
.then(prepareResponse)
.return(response);
好的,谢谢!我想我错过了一些东西,因为这将是一个很好的功能;)好的,谢谢!我想我错过了一些东西,因为这将是一个很好的功能;)