Javascript Python使用多个键对JSON对象进行分组_Javascript_Python_Json

Javascript Python使用多个键对JSON对象进行分组

javascript python json

Javascript Python使用多个键对JSON对象进行分组,javascript,python,json,Javascript,Python,Json,我有一个JSON对象，它的结构如下（JSON对象是使用从pandas数据框中提取出来的，它使用

我有一个JSON对象，它的结构如下（JSON对象是使用

从pandas数据框中提取出来的，它使用

）
我正在尝试按两个字段分组月份
和日期
预期结果：
data =  [{
            "month": "Jan",
            "details": [{
                "date": "18",
                "effort": [{
                    "activity": "cycling",
                    "duration": 3
                }, {
                    "activity": "reading",
                    "duration": 3.0
                }]
            }, {
                "date": "19",
                "effort": [{
                    "activity": "scripting",
                    "duration": 19.5
                }]
            }]
        }, {
            "month": "Feb",
            "details": [{
                "date": "18",
                "effort": [{
                    "activity": "work",
                    "duration": 22.0
                }]
            }, {
                "date": "19",
                "effort": [{
                    "activity": "cooking",
                    "duration": 0.7
                }]
            }]
        }, {
            "month": "March",
            "details": [{
                "date": "16",
                "effort": [{
                    "activity": "hiking",
                    "duration": 8.0
                }]
            }]
        }]

我尝试将数据作为python字典，使用to_dict（orient=“records”）

我得到的结果是
[{
    "month": "Jan",
    "details": [{
        "date": "18",
        "efforts": [{
            "duration": 3,
            "activity": "cycling"
        }]
    }]
}, {
    "month": "Jan",
    "details": [{
        "date": "18",
        "efforts": [{
            "duration": 3.0,
            "activity": "reading"
        }]
    }]
}, {
    "month": "Jan",
    "details": [{
        "date": "19",
        "efforts": [{
            "duration": 19.5,
            "activity": "scripting"
        }]
    }]
}, {
    "month": "Feb",
    "details": [{
        "date": "18",
        "efforts": [{
            "duration": 22.0,
            "activity": "work"
        }]
    }]
}, {
    "month": "Feb",
    "details": [{
        "date": "19",
        "efforts": [{
            "duration": 0.7,
            "activity": "cooking"
        }]
    }]
}, {
    "month": "March",
    "details": [{
        "date": "16",
        "efforts": [{
            "duration": 8.0,
            "activity": "hiking"
        }]
    }]
}]

我不处理值与现有字段的连接
尝试使用python和java脚本，你们有什么建议或解决方案吗？谢谢
这似乎有效：
代码
输出
基本上只需迭代每个条目，首先检查月份是否存在，如果存在，则检查日期是否已经存在，并相应地追加到新数据中。因此，如果不存在月份，则追加所有内容；如果不存在日期，则追加日期详细信息和新活动。如果日期也存在，则只需将活动
一个通用函数附加到组JSON。必须将字段传递给组，并为组传递键数组名称
def groupBy(vetor, campos, pos):
    if(pos >= len(campos)):
      return vetor
    gmx = campos[pos]
    agrupado = gmx["field"]
    kx = gmx["gbkey"]
    tam = len(campos)
    agrupados = {}
    saida = {}
    retorno = []    
    for l in vetor:
        lmf = {}
        for k, s in l.items():
            val_agrupado = l[agrupado]             
            if not (val_agrupado in agrupados):
                agrupados[val_agrupado] = []
            if agrupado != k:
              lmf[k] = s
        agrupados[val_agrupado].append(lmf)              
    for l in agrupados:
        agrup = agrupados[l]
        if(len(campos) > 1):            
            agrup = groupBy(agrup, campos, pos + 1)
        saida = {}
        saida[agrupado] = l
        saida[kx] = agrup
        retorno.append(saida)
    return retorno
    
data = [{'month': 'Jan','date': '18','activity': 'cycling','duration': 3},
        {'month': 'Jan', 'date': '18','activity': 'reading', 'duration': 3.0},
        {'month': 'Jan', 'date': '19', 'activity': 'scripting', 'duration': 19.5},
        {'month': 'Feb','date': '18', 'activity': 'work', 'duration': 22.0 },
        {'month': 'Feb', 'date': '19', 'activity': 'cooking','duration': 0.7},
        {'month': 'March', 'date': '16', 'activity': 'hiking', 'duration': 8.0}]
print(groupBy(data, [{'field':'month', 'gbkey': 'details'}, {'field':'date', 'gbkey': 'effort'}], 0))

它会产生类似于
[
   {
      "month":"Jan",
      "details":[
         {
            "date":"18",
            "effort":[
               {
                  "activity":"cycling",
                  "duration":3
               },
               {
                  "activity":"reading",
                  "duration":3.0
               }
            ]
         },
         {
            "date":"19",
            "effort":[
               {
                  "activity":"scripting",
                  "duration":19.5
               }
            ]
         }
      ]
   },
   {
      "month":"Feb",
      "details":[
         {
            "date":"18",
            "effort":[
               {
                  "activity":"work",
                  "duration":22.0
               }
            ]
         },
         {
            "date":"19",
            "effort":[
               {
                  "activity":"cooking",
                  "duration":0.7
               }
            ]
         }
      ]
   },
   {
      "month":"March",
      "details":[
         {
            "date":"16",
            "effort":[
               {
                  "activity":"hiking",
                  "duration":8.0
               }
            ]
         }
      ]
   }
]

请包含您尝试过的代码，以便我们查看代码中的问题。@Sevanteri使用我尝试过的代码更新我的问题。我现在面临另一个问题。你的答案在某些情况下有效，在另一些情况下失败。请检查这个。我的代码仍然有效，您刚刚更改了输入法。不要使用json.loads（data）
，而是对输入字符串使用ast.literal\u eval（data）。记得要导入ast，你能帮我解决吗this@DineshkarthikRaveendran，你也能帮我吗？
data = [{'month': 'Jan','date': '18','activity': 'cycling','duration': 3},
        {'month': 'Jan', 'date': '18','activity': 'reading', 'duration': 3.0},
        {'month': 'Jan', 'date': '19', 'activity': 'scripting', 'duration': 19.5},
        {'month': 'Feb','date': '18', 'activity': 'work', 'duration': 22.0 },
        {'month': 'Feb', 'date': '19', 'activity': 'cooking','duration': 0.7},
        {'month': 'March', 'date': '16', 'activity': 'hiking', 'duration': 8.0}]

new_data = []
not_found = True
for item in data:
    for month in new_data:
        not_found = True
        if item['month'] == month['month']:
            not_found = False
            for date in month['details']:
                if item['date'] == date['date']:
                    date['effort'].append({'activity':item['activity'], 'duration':item['duration']})
                else:
                    month['details'].append({'date':item['date'], 'effort':[{'activity':item['activity'], 'duration':item['duration']}]})
            break
    if not_found:
        new_data.append({'month':item['month'], 'details':[{'date':item['date'], \
            'effort':[{'activity':item['activity'], 'duration':item['duration']}]}]})

print new_data

[{'details': [{'date': '18', 'effort': [{'duration': 3, 'activity': 'cycling'}, {'duration': 3.0, 'activity': 'reading'}]}, {'date': '19', 'effort': [{'duration': 19.5, 'activity': 'scripting'}, {'duration': 19.5, 'activity': 'scripting'}]}], 'month': 'Jan'}, {'details': [{'date': '18', 'effort': [{'duration': 22.0, 'activity': 'work'}]}, {'date': '19', 'effort': [{'duration': 0.7, 'activity': 'cooking'}, {'duration': 0.7, 'activity': 'cooking'}]}], 'month': 'Feb'}, {'details': [{'date': '16', 'effort': [{'duration': 8.0, 'activity': 'hiking'}]}], 'month': 'March'}]

def groupBy(vetor, campos, pos):
    if(pos >= len(campos)):
      return vetor
    gmx = campos[pos]
    agrupado = gmx["field"]
    kx = gmx["gbkey"]
    tam = len(campos)
    agrupados = {}
    saida = {}
    retorno = []    
    for l in vetor:
        lmf = {}
        for k, s in l.items():
            val_agrupado = l[agrupado]             
            if not (val_agrupado in agrupados):
                agrupados[val_agrupado] = []
            if agrupado != k:
              lmf[k] = s
        agrupados[val_agrupado].append(lmf)              
    for l in agrupados:
        agrup = agrupados[l]
        if(len(campos) > 1):            
            agrup = groupBy(agrup, campos, pos + 1)
        saida = {}
        saida[agrupado] = l
        saida[kx] = agrup
        retorno.append(saida)
    return retorno
    
data = [{'month': 'Jan','date': '18','activity': 'cycling','duration': 3},
        {'month': 'Jan', 'date': '18','activity': 'reading', 'duration': 3.0},
        {'month': 'Jan', 'date': '19', 'activity': 'scripting', 'duration': 19.5},
        {'month': 'Feb','date': '18', 'activity': 'work', 'duration': 22.0 },
        {'month': 'Feb', 'date': '19', 'activity': 'cooking','duration': 0.7},
        {'month': 'March', 'date': '16', 'activity': 'hiking', 'duration': 8.0}]
print(groupBy(data, [{'field':'month', 'gbkey': 'details'}, {'field':'date', 'gbkey': 'effort'}], 0))

[
   {
      "month":"Jan",
      "details":[
         {
            "date":"18",
            "effort":[
               {
                  "activity":"cycling",
                  "duration":3
               },
               {
                  "activity":"reading",
                  "duration":3.0
               }
            ]
         },
         {
            "date":"19",
            "effort":[
               {
                  "activity":"scripting",
                  "duration":19.5
               }
            ]
         }
      ]
   },
   {
      "month":"Feb",
      "details":[
         {
            "date":"18",
            "effort":[
               {
                  "activity":"work",
                  "duration":22.0
               }
            ]
         },
         {
            "date":"19",
            "effort":[
               {
                  "activity":"cooking",
                  "duration":0.7
               }
            ]
         }
      ]
   },
   {
      "month":"March",
      "details":[
         {
            "date":"16",
            "effort":[
               {
                  "activity":"hiking",
                  "duration":8.0
               }
            ]
         }
      ]
   }
]