无法使用JSONP和Mustache JavaScript模板枚举对象中的多个节
我试图列举并构建以下fiddle with mustach.js:无法使用JSONP和Mustache JavaScript模板枚举对象中的多个节,javascript,jquery,json,jsonp,mustache,Javascript,Jquery,Json,Jsonp,Mustache,我试图列举并构建以下fiddle with mustach.js: $(function () { var choices = { "users": [ { "first_name": "Ryan", "last_name": "Pays", "pic_square": "/Global/profile/thumb/placeholder.jpg", "product_name": "Merli
$(function () {
var choices = { "users": [
{ "first_name": "Ryan",
"last_name": "Pays",
"pic_square": "/Global/profile/thumb/placeholder.jpg",
"product_name": "Merlin - the complete box set",
"product_picture": "/Global/products/full/box-set.jpg"
},
{ "first_name": "Eric",
"last_name": "Li Koo",
"pic_square": "/Global/profile/thumb/placeholder.jpg",
"product_name": "Merlin - Series 4 volume 1",
"product_picture": "/Global/products/full/box-set.jpg"
},
{ "first_name": "Abdul",
"last_name": "Raouf",
"pic_square": "/Global/profile/thumb/placeholder.jpg",
"product_name": "Merlin - the complete box set",
"product_picture": "/Global/products/full/box-set.jpg"
}]
};
$.getJSON("http://jsfiddle.net/echo/jsonp/?callback=?", choices, function (data) {
console.log(data);
var template = "<ul>{{#users}}" +
"<li>" +
"<p><strong>{{first_name}} {{last_name}}</strong> likes {{product_name}}</p>" +
"</li>" +
"{{/users}}</ul>",
html = Mustache.to_html(template, data);
$('.wrapper').html(html);
});
});
$(函数(){
变量选项={“用户”:[
{“名字”:“Ryan”,
“姓氏”:“支付”,
“pic_square”:“/Global/profile/thumb/placeholder.jpg”,
“产品名称”:“梅林-整套包装盒”,
“产品图片”:“/Global/products/full/box set.jpg”
},
{“名字”:“埃里克”,
“姓氏”:“李辜”,
“pic_square”:“/Global/profile/thumb/placeholder.jpg”,
“产品名称”:“梅林-系列4第1卷”,
“产品图片”:“/Global/products/full/box set.jpg”
},
{“名字”:“阿卜杜勒”,
“姓氏”:“Raouf”,
“pic_square”:“/Global/profile/thumb/placeholder.jpg”,
“产品名称”:“梅林-整套包装盒”,
“产品图片”:“/Global/products/full/box set.jpg”
}]
};
$.getJSON(“http://jsfiddle.net/echo/jsonp/?callback=?,选项,函数(数据){
控制台日志(数据);
var template=“{{{#users}}”+
“- ”+
“{{first_name}{{last_name}}喜欢{{product_name}}”+
“
”+
“{{/users}}
”,
html=Mustache.to_html(模板、数据);
$('.wrapper').html(html);
});
});
此处示例->
它正确地将JSON响应记录到控制台,但似乎无法构建模板。如果我只向JSONP回调传递一个用户,那么它就可以正常工作
提前谢谢。这不是你的错。JSFIDLE可以帮助您将JSON对象转换为以下格式
{"users[0][first_name]":"Ryan","users[1][first_name]":"Eric","users[2][first_name]":"Abdul","users[2][product_picture]":"/Global/products/full/box-set.jpg","users[1][product_picture]":"/Global/products/full/box-set.jpg","users[1][pic_square]":"/Global/profile/thumb/placeholder.jpg","users[1][product_name]":"Merlin - Series 4 volume 1","users[0][last_name]":"Pays","users[0][product_picture]":"/Global/products/full/box-set.jpg","users[1][last_name]":"Li Koo","users[0][product_name]":"Merlin - the complete box set","users[0][pic_square]":"/Global/profile/thumb/placeholder.jpg","users[2][last_name]":"Raouf","users[2][pic_square]":"/Global/profile/thumb/placeholder.jpg","users[2][product_name]":"Merlin - the complete box set","_":"1326530878282"}
我建议您编写自己的JSONP应用程序来避免这个问题。是我用来获取JSON对象的。将您的代码添加到问题中-JSFIDLE是一个很棒的站点,但有时速度非常慢-最好包括您的代码和JSFIDLE示例。。。。。