Javascript 将socket.io实例传递给JS对象构造函数

我阅读并尝试执行该解决方案，但是我尝试将我的

io

实例传递给对象构造函数，而不是类。我最初试图做一些像

//index.js
const {CONNECTION, CREATE_ROOM} = require('./SignalTypes')

const app = require('express')()
const server = require('http').Server(app)
const io = require('socket.io')(server)
const Lobbies = require('./lobby')

let lobbies = new Lobbies(io)

io.of('/menu').on(CONNECTION, (socket) => {
    console.log(`User connected to main menu`)

    socket.on(CREATE_ROOM, () => {
        const roomKey = lobbies.createLobby()
        socket.emit(ROOM_CREATED, roomKey)
    })
    ...
})

我的大厅文件看起来像

//lobby.js
const shortid = require('shortid')

function Lobbies(io) {
    this.io = io;
    this.lobbies = {}
}

Lobbies.prototype.createLobby = () => {
    let roomKey = shortid.generate()

    //create namespace for new lobby
    const lobbyNamespace = this.io.of(`/${roomKey}`)  // issue
    
    this.lobbies[roomKey] = new Lobby(roomKey, lobbyNamespace)
    return roomKey
}
//Lobby object constructor defined later
...
module.exports = Lobbies

但是，我不断遇到错误，它说，

io

在行中未定义

//lobby.js
const lobbyNamespace = this.io.of(`/${roomKey}`)
//TypeError: Cannot read property 'of' of undefined

---

我想知道是否有一种方法可以将我的

io

对象传递给我的对象构造函数，而不必将其更改为ES6类或其他什么。有什么建议吗？

当使用箭头函数语法时，您将丢失此

参考。我不知道您为什么要使用旧的、难以理解的语法，但如果您想使用这种语法而不是类，您应该：

Lobbies.prototype.createLobby = function() {
    let roomKey = shortid.generate()

    //create namespace for new lobby
    const lobbyNamespace = this.io.of(`/${roomKey}`)  // issue
    
    this.lobbies[roomKey] = new Lobby(roomKey, lobbyNamespace)
    return roomKey
}