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Javascript 如何使用dhtmlx uploader上载文件_Javascript_Asp.net_Dhtmlx - Fatal编程技术网

Javascript 如何使用dhtmlx uploader上载文件

Javascript 如何使用dhtmlx uploader上载文件,javascript,asp.net,dhtmlx,Javascript,Asp.net,Dhtmlx,我在应用程序中使用dhtmlx上传程序。我想上传单个/多个文件,上传的文件名和内容必须保存在数据库中。在.cshtml文件中,我实现了 var myForm, formData; formData = [{ type: "fieldset", label: "Uploader", list: [{ type: "upload", name

我在应用程序中使用dhtmlx上传程序。我想上传单个/多个文件,上传的文件名和内容必须保存在数据库中。在.cshtml文件中,我实现了

   var myForm, 
    formData;
    formData = [{
            type: "fieldset",
            label: "Uploader",
            list: [{
                type: "upload",
                name: "myFiles",
                inputWidth: 330,
                url: "/Home/AddFile",
                }]
        }];
            myForm = new dhtmlXForm("myForm", formData);
如何将上传的文件以内容和名称保存在数据库中

   var myForm, 
    formData;
    formData = [{
            type: "fieldset",
            label: "Uploader",
            list: [{
                type: "upload",
                name: "myFiles",
                inputWidth: 330,
                url: "/Home/AddFile",
                }]
        }];
            myForm = new dhtmlXForm("myForm", formData);
<form method="post" enctype="multipart/form-data" name="partmasterform">
<div id="myForm" style="position: relative; top: 20px;width: 100%; height: 700px; aborder: #B5CDE4 1px solid;"></div>
</form>
然后您必须读取文件并将内容存储到db

   var myForm, 
    formData;
    formData = [{
            type: "fieldset",
            label: "Uploader",
            list: [{
                type: "upload",
                name: "myFiles",
                inputWidth: 330,
                url: "/Home/AddFile",
                }]
        }];
            myForm = new dhtmlXForm("myForm", formData);