你能帮我把JavaScript代码简化成几行吗？

我有一个JavaScript代码，可以获取当前通过API播放的歌曲的歌词

有时（并非总是）歌词会在开头返回标题，这正是我想要删除的

有时开头的标题是大写的，有时是大写和小写的

例如：

SWEET CHILD O' MINE

She's got a smile that it seems to me

Reminds me of childhood memories

Where everything was as fresh as the bright blue sky

Now and then when I see her face

She takes me away to that special place

And if I stare too long, I'd probably break down and cry
........

我创建了一个有点麻烦的代码，成功地从一开始就删除了标题

我想看看他们是否能帮助我在更少的行中简化代码

我将分享代码中我们感兴趣的部分，以便于帮助，如果你想要所有的代码，我没有问题分享它

currentSong

包含正在播放的歌曲的标题

lyric

包含通过API获得的完整歌词

this.refreshLyric = function(currentSong, currentArtist) {
    
    //another code that does not interest
    //...
    //...
    
    //lyric variable contains the complete lyrics of a song obtained through an API
    var lyric = data.mus[0].text;

    
    //divide the string CurrentSong (contains the song title) into parts
    let splitCurrenSong = currentSong.split(' ');
    
    //I get the length of the array
    let largeCurrentSong = splitCurrenSong.length;
    
    //divide the string lyric into parts                            
    let splitLyric = lyric.split(' ');
                    
    //I get the first elements of the lyric array with the length limit of largeCurrentSong
    let pieceLyric = splitLyric.slice(0, largeCurrentSong);
    
    //I get all elements of the splitCurrenSong array
    let pieceSong = splitCurrenSong.slice(0, largeCurrentSong);
    
    //join arrays 
    let joinLyric = pieceLyric.join(' ');
    let joinSong = pieceSong.join(' ');
        
        //I check if the chunk of the joinLyric string matches the same chunk of joinSong
        if (joinLyric.toLocaleLowerCase() == joinSong.toLocaleLowerCase()) {
            //remove the matching items
            splitLyric.splice(0, largeCurrentSong);
            //put the resulting join array into a variable
            lyrics = splitLyric.join(' ');
            //remove the spaces from the beginning and end of lyrics
            lyric = lyrics.trim()
        }   
    
    //another code that does not interest
    //...
    //...

}

编辑：回复@iamaword

如API返回的屏幕截图所示：

文本：

包含完整歌曲的歌词

名称：

歌曲标题

用这句话我完全可以知道这首歌的名字：

var nameSong=data.mus[0]。名称

但是我不认为这是必要的，因为我从

currentSong

变量中获取歌曲的名称，这是在

get

命令中发送的获取歌词的变量

最终编辑：归功于@cerbiralfart

完整代码：

this.refreshLyric = function(currentSong, currentArtist) {
        
      var proxy_URL = PROXYURL;
      var vagalume_api = 'https://api.vagalume.com.br/search.php?';
      
      var xhttp = new XMLHttpRequest();
      xhttp.onreadystatechange = function() {
        if (this.readyState === 4) {
          if (this.status === 200) {
             var data = JSON.parse(this.responseText);

                    if (data.type === 'exact' || data.type === 'aprox') {
                        var lyric = normalizeText(data);

                                                                        
                        document.getElementById('lyric').innerHTML = lyric.replace(/\n/g, '<br />');
                        var openLyric = document.getElementsByClassName('lyrics')[0];
                        openLyric.style.opacity = "1";
                        openLyric.setAttribute('data-toggle', 'modal');
                        var powered = "Vagalume"
                        var URL_lyric = 'https://www.vagalume.com.br';
                        
                        //Powered by image src...
                        const parent = document.querySelector('.chartlyrics');
                        parent.innerHTML = '';
                        var img = document.createElement("img");
                        img.src = "img/103-fundo-escuro.jpg"
                        img.setAttribute('class', "")
                        parent.appendChild(img);
                        parent.appendChild(document.createElement('br'));
                        parent.append('Powered by ');
                        
                        // Powered by link a href...                        
                        document.getElementById('powered_by').innerHTML = ''
                        var a = document.getElementById('powered_by')
                          .appendChild(document.createElement("a"));
                          
                        a.href = URL_lyric;
                        a.target = "_blank";
                        a.rel = "noopener noreferrer";
                        a.textContent = powered;
                    } else {
                        var page = new Page();
                        page.refreshLyric2(currentSong, currentArtist);
                    }
                } else {
                   var page = new Page();
                    page.refreshLyric2(currentSong, currentArtist);
                   }
            }
        }
            xhttp.open('GET', proxy_URL + vagalume_api + API_KEY + '&art=' + currentArtist + '&mus=' + currentSong.toLowerCase(), true);
            xhttp.send()
    }

function normalizeText(response){
  // First unpack the data, get the right name and text values
  let {mus:[{name, text}]} = response;

  // Now get the part of the text that might be the title
  let titleLength = name.length;
  let maybeTitle = text.substring(0, titleLength);

  // Compare the two titles and trim if they match
  if (name.toLowerCase() === maybeTitle.toLowerCase() && exceptions.includes(maybeTitle.toLowerCase()) == false){
    text = text.substring(titleLength)
  }
  
  //Remove any leading or trailing whitespace and return
  return text.trim();
}

//song names excepted from being removed in lowercase ['one song', 'two song', etc..]
const exceptions = ['sweet emotion'];

我在

normalizeText

函数中添加了一个新条件，以检查要删除的歌曲名称是否不在异常范围内

// Compare the two titles and trim if they match
      if (name.toLowerCase() === maybeTitle.toLowerCase() && exceptions.includes(maybeTitle.toLowerCase()) == false){

我创建了一个常量

exceptions

，其中必须手动添加小写歌曲名称，并用逗号分隔

//song names excepted from being removed in lowercase ['one song', 'two song', etc..]
    const exceptions = ['sweet emotion'];

---

有几种方法可以清理代码，主要是如何解包数据以及如何比较两个字符串

function normalizeText(response){
  // First unpack the data, get the right name and text values
  let {mus:[{name, text}]} = response;

  // Now get the part of the text that might be the title
  let titleLength = name.length;
  let maybeTitle = text.substring(0, titleLength);

  // Compare the two titles and trim if they match
  if (name.toLowerCase() === maybeTitle.toLowerCase()){
    text = text.substring(titleLength)
  }
  
  //Remove any leading or trailing whitespace and return
  return text.trim();
}

---

编辑：sintax error toLowerCase added（）

歌词是否带有换行符，您可以通过类似正则表达式的歌词进行拆分。拆分（/\r？\n/）是的，歌词带有\nalso*您可以通过从中获取歌词的相同api获取标题吗？因为如果可以的话，你可以对第一段歌词做一些检查，看看它们是否与标题匹配，标题也可以通过相同的API获得。我在newline上拆分，然后知道第一个数组将是标题（或不是）。这至少可以将其缩小到确定特定字符串是否为标题的路径。我已编辑以共享完整的代码，因为我不知道如何在我的代码中实现该函数。所有此函数都以

data

作为参数，而不是行

var lyric=data.mus[0]。text通过
结束我提议的代码
：使用
const-lyric=normalizeText（数据）
我修复了
中的一个小错误。toLowerCase
缺少括号，现在它可以工作了。抱歉@Cerberalfart，我敢编辑你的答案，但是我需要社区信任成员的批准才能完成编辑。我非常感谢你的正确回答
function normalizeText(response){
  // First unpack the data, get the right name and text values
  let {mus:[{name, text}]} = response;

  // Now get the part of the text that might be the title
  let titleLength = name.length;
  let maybeTitle = text.substring(0, titleLength);

  // Compare the two titles and trim if they match
  if (name.toLowerCase() === maybeTitle.toLowerCase()){
    text = text.substring(titleLength)
  }
  
  //Remove any leading or trailing whitespace and return
  return text.trim();
}