Javascript extjs5 widgetcolumn在单个单元格中包含多个小部件

我创建了一个widgetcolumn作为包含多个组件的面板。如何将记录参数与这些组件链接

例如：

{
    xtype: 'widgetcolumn',
    dataIndex: 'data',
    widget: {
        xtype: 'panel',
        height: 77,
        width: 642,
        layout: {
            type: 'vbox',
            align: 'stretch'
        },
        items: [
            {
                xtype: 'button',
                text: record.get('name')    //<<-- how can i link this record from the grid with this component?
            },
            {
                xtype: 'button',
                text: record.get('type')    //<<-- how can i link this record from the grid with this component?
            },
            {
                xtype: 'button',
                text: record.get('location')    //<<-- how can i link this record from the grid with this component?
            }
        ]
    }
}

也许，我可以通过渲染器功能访问记录？大概是这样的：

 renderer: function(value, meta, record) {
    //How can I get access to widget instance?
 }

---

我解决了这个问题。我们需要访问父元素widgetcolumn，然后调用函数getWidgetRecord

{
xtype: 'label',
text: 'Some text...',
cls: 'gridcall-label-asgmt',
listeners: {
    resize: function(label) {
        var parent = label.up();
        while(typeof parent.up() !== 'undefined') {
            parent = parent.up();
        }   // --- while

        var record = parent.getWidgetRecord();
        if (typeof record === 'undefined') return;

        label.setText(record.data.asgmt, false);
    }   // --- resize
}   // --- listeners

---

}我解决了这个问题。我们需要访问父元素widgetcolumn，然后调用函数getWidgetRecord

{
xtype: 'label',
text: 'Some text...',
cls: 'gridcall-label-asgmt',
listeners: {
    resize: function(label) {
        var parent = label.up();
        while(typeof parent.up() !== 'undefined') {
            parent = parent.up();
        }   // --- while

        var record = parent.getWidgetRecord();
        if (typeof record === 'undefined') return;

        label.setText(record.data.asgmt, false);
    }   // --- resize
}   // --- listeners

---

}我解决了这个问题。我们需要访问父元素widgetcolumn，然后调用函数getWidgetRecord

{
xtype: 'label',
text: 'Some text...',
cls: 'gridcall-label-asgmt',
listeners: {
    resize: function(label) {
        var parent = label.up();
        while(typeof parent.up() !== 'undefined') {
            parent = parent.up();
        }   // --- while

        var record = parent.getWidgetRecord();
        if (typeof record === 'undefined') return;

        label.setText(record.data.asgmt, false);
    }   // --- resize
}   // --- listeners

---

}我解决了这个问题。我们需要访问父元素widgetcolumn，然后调用函数getWidgetRecord

{
xtype: 'label',
text: 'Some text...',
cls: 'gridcall-label-asgmt',
listeners: {
    resize: function(label) {
        var parent = label.up();
        while(typeof parent.up() !== 'undefined') {
            parent = parent.up();
        }   // --- while

        var record = parent.getWidgetRecord();
        if (typeof record === 'undefined') return;

        label.setText(record.data.asgmt, false);
    }   // --- resize
}   // --- listeners

}