Javascript 如何通过单击第一个div值在第二个div中显示一个div值
以下是我的html代码:Javascript 如何通过单击第一个div值在第二个div中显示一个div值,javascript,html,ajax,Javascript,Html,Ajax,以下是我的html代码: <html> </head> <body> <div id="link"> <a href="http://www.google.com">google</a> </div> <div id="result"></div> </body> </html> </html>
<html>
</head>
<body>
<div id="link">
<a href="http://www.google.com">google</a>
</div>
<div id="result"></div>
</body>
</html>
</html>
<script src="https://www.google.com/jsapi" type="text/javascript"></script> <script language="Javascript" type="text/javascript"> google.load('search', '1'); $('a').live('click',function OnLoad() { // Create a search control var searchControl = new google.search.SearchControl(); // Add in a full set of searchers var localSearch = new google.search.LocalSearch(); searchControl.addSearcher(localSearch); searchControl.addSearcher(new google.search.WebSearch()); searchControl.addSearcher(new google.search.VideoSearch()); searchControl.addSearcher(new google.search.BlogSearch()); searchControl.addSearcher(new google.search.NewsSearch()); searchControl.addSearcher(new google.search.ImageSearch()); searchControl.addSearcher(new google.search.BookSearch()); searchControl.addSearcher(new google.search.PatentSearch()); // Set the Local Search center point localSearch.setCenterPoint("New York, NY"); // tell the searcher to draw itself and tell it where to attach searchControl.draw(document.getElementById("searchcontrol")); // execute an inital search searchControl.execute("VW GTI"); } google.setOnLoadCallback(OnLoad); </script>
我想要这样的输出
点击谷歌,然后在那里显示结果在其他div 谢谢试试看。。。load('search','1'); $('a').live('click',函数OnLoad(){ //创建搜索控件 var searchControl=new google.search.searchControl(); //添加一整套搜索程序 var localSearch=new google.search.localSearch(); searchControl.addSearcher(localSearch); searchControl.addSearcher(新的google.search.WebSearch()); searchControl.addSearcher(新的google.search.VideoSearch()); searchControl.addSearcher(新的google.search.BlogSearch()); searchControl.addSearcher(新的google.search.NewsSearch()); searchControl.addSearcher(新的google.search.ImageSearch()); searchControl.addSearcher(新的google.search.BookSearch()); searchControl.addSearcher(新的google.search.PatentSearch()); //设置本地搜索中心点 localSearch.setCenterPoint(“纽约州纽约市”); //告诉搜索者自己画出来,并告诉它连接到哪里 searchControl.draw(document.getElementById(“searchControl”); //执行初始搜索 searchControl.execute(“大众GTI”); } setOnLoadCallback(OnLoad);
最好的方法是制作两个不同的网页(您的初始页面和结果),然后将它们放入iframe中。您可以在此处看到演示:尝试下面的javascript代码<?php $ch = curl_init($_POST['action']); curl_setopt($ch, CURLOPT_POST, FALSE); //curl_setopt($ch, CURLOPT_URL, $r->event_url); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $html = curl_exec($ch); curl_close($ch); echo $html; ?>
试试它的工作…var el=document.getElementById(“结果”); el.innerHTML=“”;
首先创建一个PHP文件:- <body> <div id="link"> <a href="javascript:void(0)" onclick="result('https://www.google.co.in/')">google</a> </div> <div id="result" height="200" width="200"></div> </body>
函数结果(url)
{
$.ajax({url:'one.php',
数据:{action:url},
键入:“post”,
成功:函数(输出){
$('#result').html(输出);
}
});
}
导航到www.google.com的结果?或者搜索某物的结果?你可能想要一个
iframe
到目前为止你对ajax做了哪些尝试?iframe没有任何用处使用任何其他…@polin我没有尝试过ajax帮助如果你对它们有一些了解请回答美术师的问题,这很重要。他们在谷歌做了一切来防止google.com在任何其他地方打开,但在它自己的选项卡或窗口中。。。
<body>
<div id="link">
<a href="javascript:void(0)" onclick="result('https://www.google.co.in/')">google</a>
</div>
<div id="result" height="200" width="200"></div>
</body>