Warning: file_get_contents(/data/phpspider/zhask/data//catemap/3/xpath/2.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Javascript 带结束承诺的等待函数_Javascript_Firebase_Google Cloud Firestore - Fatal编程技术网

Javascript 带结束承诺的等待函数

Javascript 带结束承诺的等待函数,javascript,firebase,google-cloud-firestore,Javascript,Firebase,Google Cloud Firestore,我试图从firebase获取一个集合,然后调用一个函数来插入数据。问题是在比较函数结束之前调用了插入数据 这是我遵循的指南: 1-获取游戏输入,并创建一个包含要推荐的视频的阵列 2-从用户处获取已推荐的视频 3-将视频与阵列进行比较,以排除重复的视频 4-继续执行下一个函数,将阵列插入firebase 问题是,对于第4步,我需要完成第3步。但事实并非如此。有没有关于如何解决这个问题的建议 export const generateRecommendationsFromGame = (partic

我试图从firebase获取一个集合,然后调用一个函数来插入数据。问题是在比较函数结束之前调用了插入数据

这是我遵循的指南:

1-获取游戏输入,并创建一个包含要推荐的视频的阵列

2-从用户处获取已推荐的视频

3-将视频与阵列进行比较,以排除重复的视频

4-继续执行下一个函数,将阵列插入firebase

问题是,对于第4步,我需要完成第3步。但事实并非如此。有没有关于如何解决这个问题的建议

export const generateRecommendationsFromGame = (participantID) => {
  var newRec = [];
  let userRef = firebase.firestore().collection("users").doc(participantID);


  //1 Game inputs
  return firebase.firestore().collection("inputGame").where("user", "==", userRef).onSnapshot({}, function(querySnapshot) {
    querySnapshot.forEach(function(doc) {
      let consagua = doc.data().consagua;
      let enfart = doc.data().enfartamento;
      let mastig = doc.data().mastigacao;
      let mexdorm = doc.data().mexerdormir;
      let emoc = doc.data().emocoes;

      //13
      //V2.3.2
      if (Number(consagua) >= 3) {
        newRec.push('V2.3.2');
      }
      //15
      //V3.1
      if (Number(enfart) >= 25) {
        newRec.push('V3.1');
      }
      //16
      //V3.2
      if (Number(mastig) >= 40) {
        newRec.push('V3.2');
      }
      //17
      //V3.3
      //18
      //V3.4
      if (Number(mexdorm) >= 3) {
        newRec.push('V3.3');
        newRec.push('V3.4');
      }
      //19
      //V3.5
      if (Number(emoc) >= 2) {
        newRec.push('V3.5');
      }


      //2 - User Videos
      return firebase.firestore().collection("recommendedVideo").where("user", "==", userRef).get().then(result2 => {
        result2.forEach(doc2 => {

          //3 - Get video ref to compate to Array
          var videoFef = doc2.data().video.id;
          firebase.firestore().collection("videos").doc(videoFef).get().then(
            function(doc2) {
              if (doc2.exists) {
                var sequence = doc2.data().sequenceNumberID;
                for (var i = 0; i < newRec.length; i++) {
                  if (String(sequence) == String(newRec[i])) {
                    var index = newRec.indexOf(newRec[i]);
                    if (index > -1) {
                      newRec.splice(index, 1);
                    }
                  }
                }
              } else alert("Não existe doc videos");
            }
          )
        });
      }).then(() => {
         insertData(newRec);
      })
    });
  })
};
export const generaterecommissionsfromgame=(participantID)=>{
var newRec=[];
让userRef=firebase.firestore().collection(“users”).doc(participantID);
//1游戏输入
返回firebase.firestore().collection(“inputGame”).where(“user”,“==”,userRef).onSnapshot({},函数(querySnapshot){
querySnapshot.forEach(函数(doc){
设consagua=doc.data().consagua;
设enfart=doc.data().enfartamento;
设mastig=doc.data().mastigacao;
让mexform=doc.data().mexerdormir;
设emoc=doc.data().emocoes;
//13
//V2.3.2
如果(数量(consagua)>=3){
新记录推送(“V2.3.2”);
}
//15
//V3.1
如果(数字(enfart)>=25){
newRec.push('V3.1');
}
//16
//V3.2
如果(数量(mastig)>=40){
newRec.push('V3.2');
}
//17
//V3.3
//18
//V3.4
如果(数字(mexform)>=3){
newRec.push('V3.3');
newRec.push('V3.4');
}
//19
//V3.5
如果(编号(emoc)>=2){
newRec.push('V3.5');
}
//2-用户视频
返回firebase.firestore().collection(“recommendedVideo”).where(“user”,“==”,userRef.get()。然后(result2=>{
结果2.forEach(doc2=>{
//3-获取视频参考以兼容阵列
var videoFef=doc2.data().video.id;
firebase.firestore().collection(“videos”).doc(videoFef.get()。然后(
功能(doc2){
如果(doc2.exists){
var sequence=doc2.data().sequenceNumberID;
对于(变量i=0;i-1){
新接头(索引1);
}
}
}
}else alert(“Não existe doc视频”);
}
)
});
}).然后(()=>{
插入数据(newRec);
})
});
})
};
然后,在比较视频并排除重复的视频后,我想调用函数在Firebase上插入视频

export const insertData= (arr) => {   
  var newRec = arr.split(',');
  for (var i = 0; i < newRec.length; i++) {
    var ref = newRec[i];
    firebase.firestore().collection("videos").where("sequenceNumberID", "==", ref.toString()).onSnapshot(function (querySnapshot) {
      querySnapshot.forEach(function (doc) {
        firebase.firestore().collection("recommendedVideo").add({
          seen: false,
          user: firebase.firestore().collection('users').doc(participantID),
          video: firebase.firestore().collection('videos').doc(doc.id)
        }).catch(function (error) {
          alert(error);
        })
      });
    });
  }
}
export const insertData=(arr)=>{
var newRec=arr.split(',');
对于(变量i=0;i
您需要对每个
doc2
进行异步查询,然后在所有查询完成后继续执行
insertData
。正确的工具是
Promise.all
,它接受一个承诺数组,并在数组中的所有承诺都被解析后解析。因此,将每个
doc2
映射到一个承诺

除了
Promise.all
,还可以使用
async
/
wait
来大大降低成本

请注意,您正在对
forEach
中的
doc2
变量进行阴影(复制),这很容易引起混淆-最好将其命名为其他名称(例如
doc3
):

使
querySnapshot.forEach
异步:

querySnapshot.forEach(async (doc) => {
然后:

//2 - User Videos
const result2 = await firebase.firestore().collection("recommendedVideo").where("user", "==", userRef).get();
await Promise.all(result2.map(async (doc2) => {
  //3 - Get video ref to compate to Array
  const videoFef = doc2.data().video.id;
  const doc3 = await firebase.firestore().collection("videos").doc(videoFef).get();
  if (!doc3.exists) {
    alert("Não existe doc videos");
    return;
  }
  var sequence = doc3.data().sequenceNumberID;
  for (var i = 0; i < newRec.length; i++) {
    if (String(sequence) !== String(newRec[i])) return;
    var index = newRec.indexOf(newRec[i]);
    if (index > -1) newRec.splice(index, 1);
  }
}));
// end of Promise.all
insertData(newRec);
//2-用户视频
const result2=await firebase.firestore().collection(“recommendedVideo”).where(“user”、“==”、userRef.get();
等待承诺.all(result2.map)(异步(doc2)=>{
//3-获取视频参考以兼容阵列
const videoFef=doc2.data().video.id;
const doc3=wait firebase.firestore().collection(“videos”).doc(videoFef.get();
如果(!doc3.存在){
警报(“Não existe doc视频”);
返回;
}
var sequence=doc3.data().sequenceNumberID;
对于(变量i=0;i-1)新接头(索引,1);
}
}));
//承诺的结束
插入数据(newRec);

以下是我如何解决这个问题的

        var reads = [];

        await firebase.firestore().collection("recommendedVideo").where("user", "==", userRef).onSnapshot({}, function (querySnapshot) {
            querySnapshot.forEach(async doc => {
                reads.push(doc);
            })
            return Promise.all(reads.map(async (doc1) => {
                //3 - Get video ref to compate to Array
                const videoFef = doc1.data().video.id;
                const doc3 = await firebase.firestore().collection("videos").doc(videoFef).get();
                if (!doc3.exists) {
                    alert("Não exisste doc videos");
                    return;
                }

                var sequence = doc3.data().sequenceNumberID;
                for (var i = 0; i < newRec.length; i++) {
                    if (String(sequence) == String(newRec[i])) {
                        var index = newRec.indexOf(newRec[i]);
                        if (index > -1) {
                            newRec.splice(index, 1);
                        }
                    }
                }
            })).then(function() {
                insertData(newRec, participantID);
            });
        });
var reads=[];
等待firebase.firestore().collection(“recommendedVideo”).where(“user”,“==”,userRef).onSnapshot({},函数(querySnapshot){
querySnapshot.forEach(异步文档=>{
读。推(doc);
})
返回Promise.all(reads.map)(异步(doc1)=>{
//3-获取视频参考以兼容阵列
const videoFef=doc1.data().video.id;
const doc3=wait firebase.firestore().collection(“videos”).doc(videoFef.get();
如果(!doc3.存在){
警报(“Não exisste doc视频”);
返回;
}
var sequence=doc3.data().sequenceNumberID;
对于(变量i=0;i-1){