从数据库中获取值并使用xml显示在jqgrid表中?

从数据库中获取值并使用xml显示在jqgrid表中?,jqgrid,Jqgrid,这个网格函数 $(document).ready(function () { $("#gridTable").jqGrid({ url: '/Grid/CallingFunction', datatype: 'xml', colNames: ['Name', 'Empno', 'Age', 'Address', 'Contactno', 'Sal

这个网格函数

$(document).ready(function () {
                $("#gridTable").jqGrid({
                    url: '/Grid/CallingFunction',
                    datatype: 'xml',
                    colNames: ['Name', 'Empno', 'Age', 'Address', 'Contactno', 'Salary'],
                    colModel: [
                        {name: 'name', width: 200},
                        {name: 'empno', width: 100},
                        {name: 'age', width: 100},
                        {name: 'address', width: 100},
                        {name: 'contactno', width: 100},
                        {name: 'salary', width: 100}
                    ],
                    rowNum: 20,
                    height: 400,
                    autoWidth: true,
                    rowList: [5, 10, 15],
                    pager: '#gridPager',
                    multiselect: true,
                    viewrecords: true,
                    caption: "Employee Details"
                }).navGrid("#gridPager", {edit: false, add: false, del: 'deletetext;', refreshtext: 'Refresh ', searchtext: 'Find '});
            });
        </script>
    </head>
    <body>
        <table id="gridTable" ></table>
        <div id="gridPager"></div>
    </body>
}

//这叫funtcion

 protected void doPost(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        response.setContentType("text/xml");
        try (PrintWriter out = response.getWriter()) {
            ConnectionClass connectionclass = new ConnectionClass();
            String xml = connectionclass.Database();
            response.getWriter().write(xml);
        } catch (NumberFormatException e) {
            System.out.println(e);
        }
    }

这里有几件事。您需要使用编辑器({}按钮)中的代码格式格式化代码。此外,如果您描述了您期望发生的事情和实际发生的事情,它也会有所帮助。如何使用ajax在jqgrid中显示数据库值..使用xml或json
 protected void doPost(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        response.setContentType("text/xml");
        try (PrintWriter out = response.getWriter()) {
            ConnectionClass connectionclass = new ConnectionClass();
            String xml = connectionclass.Database();
            response.getWriter().write(xml);
        } catch (NumberFormatException e) {
            System.out.println(e);
        }
    }