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Jquery mobile jquerylistview问题_Jquery Mobile - Fatal编程技术网

Jquery mobile jquerylistview问题

Jquery mobile jquerylistview问题,jquery-mobile,Jquery Mobile,工作。在listview中显示2个值 {"liste":{"TotalRecordCount":"2","xmlns":"","dokuman":[{"id":"2568","titles":"İstanbul Eindhoven"},{"id":"2384","titles":"Kesişen Dünyalar",}]}} 不工作。在listview中似乎不是1个值 {"liste":{"TotalRecordCount":"1","xmlns":"","dokuman":{"id":"20

工作。在listview中显示2个值

{"liste":{"TotalRecordCount":"2","xmlns":"","dokuman":[{"id":"2568","titles":"İstanbul Eindhoven"},{"id":"2384","titles":"Kesişen Dünyalar",}]}}
不工作。在listview中似乎不是1个值

{"liste":{"TotalRecordCount":"1","xmlns":"","dokuman":{"id":"2085","titles":"Fotoğraf Atölyesi"}}}
我的listview添加代码

path=data.liste.dokuman;

for (var liindex = 0;liindex<path.length; liindex++){
   // my listview adding value
   }
path=data.liste.dokuman;

对于(var liindex=0;liindexJson,如果任何Json数组中可能有多个结果,则应使用正确的格式。
因此,您的Json应该如下所示:

{"liste":{"TotalRecordCount":"1","xmlns":"","dokuman":[{"id":"2085","titles":"Fotoğraf Atölyesi"}]}} 
那么你上面的代码就可以工作了。 否则,按以下方式获取单记录JsonObject的数据

var id=data.liste.dokuman.id ;
var titles = data.liste.dokuman.id.titles;
等等..

工作:)谢谢@neeraj

if(path.length == undefined){
              myNewArray[0]= path;
              console.log("not array")
         }