Jquery 如何在轮询ajax时填充子网格,然后在jqgrid中应用现有网格?
我使用了列表json,并且在我希望每隔6秒从db附加数据并使用相同的列表json格式后得到了正确的答案。在没有子网格系统的情况下,它也可以正常工作,但在我得到正确的父轮询数据后,我正在集成这两个数据,但我没有得到子网格数据(为子网格精细获取数据后端) 在Oleg评论后第二次更新代码我已附上代码请查找Jquery 如何在轮询ajax时填充子网格,然后在jqgrid中应用现有网格?,jquery,jqgrid,Jquery,Jqgrid,我使用了列表json,并且在我希望每隔6秒从db附加数据并使用相同的列表json格式后得到了正确的答案。在没有子网格系统的情况下,它也可以正常工作,但在我得到正确的父轮询数据后,我正在集成这两个数据,但我没有得到子网格数据(为子网格精细获取数据后端) 在Oleg评论后第二次更新代码我已附上代码请查找 var $grid = $("#list11"), mainGridPrefix = "s_"; jQuery("#list11").jqGrid({ url: 'serv
var $grid = $("#list11"),
mainGridPrefix = "s_";
jQuery("#list11").jqGrid({
url: 'server.php?getList',
datatype: "json",
data: firstListJson,
height: 200,
colNames: ['Inv No', 'Date', 'Client'],
colModel: [{
name: 'id',
index: 'id',
width: 55
}, {
name: 'invdate',
index: 'invdate',
width: 90
}, {
name: 'name',
index: 'name',
width: 100
}],
rowNum: 10,
gridview: true,
rowList: [10, 20, 30],
pager: '#pager11',
loadonce: false,
sortname: 'id',
viewrecords: true,
idPrefix: mainGridPrefix,
sortorder: "desc",
multiselect: false,
caption: "Subgrid With polling",
jsonReader: {
repeatitems: false,
id: 'id'
},
beforeProcessing: function(data) {
var rows = data,
l = data.length,
i, item, subgrids = {};
for (i = 0; i < l; i++) {
item = rows[i];
if (item.subGridData) {
subgrids[item.id] = item.subGridData;
}
}
//alert(subgrids);
data.userdata = subgrids;
},
subGrid: true,
subGridRowExpanded: function(subgridDivId, rowId) {
var subGridID = $("#" + subgridDivId + "_t");
var $subgrid = $("<table id='" + subgridDivId + "_t'></table>"),
pureRowId = $.jgrid.stripPref(mainGridPrefix, rowId),
subgrids = $(this).jqGrid("getGridParam", "userData");
$subgrid.appendTo("#" + $.jgrid.jqID(subgridDivId));
$subgrid.jqGrid({
datatype: "local",
data: subgrids[pureRowId],
colNames: ['Emp ID', 'Name', 'Age'],
colModel: [{
name: 'id',
index: 'id',
width: 55
}, {
name: 'name',
index: 'name',
width: 90
}, {
name: 'age',
index: 'age',
width: 100
}],
rowNum: 10,
rowList: [10, 20, 30],
sortname: 'id',
viewrecords: true,
sortorder: "desc",
multiselect: false
});
}
});
jQuery("#list11").jqGrid('navGrid', '#pager11', {
add: false,
edit: false,
del: false
});
Below code
for json list of list
var firstListJson = [{
"id": "01",
"invdate": "2014-07-24",
"name": "John",
"subGridData": [{
"id": "01",
"name": "Krishna",
"age": "28"
}, {
"id": "01",
"name": "Jai",
"age": "28"
}, {
"id": "01",
"name": "Suresh",
"age": "28"
}]
}, {
"id": "02",
"invdate": "2014-07-24",
"name": "Hill",
"subGridData": [{
"id": "01",
"name": "Mani",
"age": "28"
}, {
"id": "01",
"name": "Raj",
"age": "28"
}, {
"id": "01",
"name": "Main",
"age": "28"
}]
}];
Below code
for polling code
function pollData() {
var pollingListUrl = 'server.php?getPollList';
$.ajax({
type: "POST",
url: pollingListUrl,
contentType: "application/json; charset=utf-8",
dataType: "json",
async: true,
cache: false,
success: function(data) {
var $mygrid = $("#list11");
$mygrid.jqGrid("addRowData", "id", data);
$mygrid.trigger("reloadGrid", [{
current: true
}]);
},
error: function(x, e) {
alert("error occur");
}
});
}
var$grid=$(“#列表11”),
mainGridPrefix=“s”;
jQuery(“#list11”).jqGrid({
url:'server.php?getList',
数据类型:“json”,
数据:firstListJson,
身高:200,
colNames:['Inv No','Date','Client'],
colModel:[{
名称:“id”,
索引:“id”,
宽度:55
}, {
名称:“invdate”,
索引:“invdate”,
宽度:90
}, {
姓名:'姓名',
索引:“名称”,
宽度:100
}],
rowNum:10,
gridview:没错,
行列表:[10,20,30],
传呼机:'#第11页',
loadonce:false,
sortname:'id',
viewrecords:是的,
idPrefix:mainGridPrefix,
巫师:“描述”,
多选:错,
标题:“带轮询的子网格”,
jsonReader:{
重复项:false,
id:'id'
},
预处理前:函数(数据){
变量行=数据,
l=数据长度,
i、 项,子网格={};
对于(i=0;i
我发现您的代码中有3个错误:
数据类型:“xml”
,但处理前的代码面向代码,其中数据
是对象,而不是xml文档
顺便说一下,我严格建议您在网格和子网格中添加gridview:true
,以提高性能
$mygrid.jqGrid(“addRowData”,“ID”,data);
但是网格中不包含列“ID”
。您应该使用“ID”
subGridData
部分数据中使用了不必要的“
。即使是您发布的代码中的颜色(我的意思是美化突出显示),也会显示相同的效果
var firstListJson=[
{“id”:“01”,“invdate”:“2014-07-24”,“name”:“John”,
“子网格数据”:[{
“id”:“01”,“姓名”:“奎师那”,“年龄”:“28”},
{“id”:“01”,“name”:“Jai”,“age”:“28”},
{“id”:“01”,“姓名”:“Suresh”,“年龄”:“28”}
]"},
{“id”:“02”,“invdate”:“2014-07-24”,“name”:“Hill”,
“子网格数据”:[{
“id”:“01”,“姓名”:“马尼”,“年龄”:“28”},
{“id”:“01”,“name”:“Raj”,“age”:“28”},
{“id”:“01”,“name”:“Main”,“age”:“28”}
]"}
];
应该使用
var firstListJson=[
{"id":"01","invdate":"2014-07-24","name":"John",
"subGridData": [{
"id":"01","name":"Krishna","age":"28"},
{"id":"01","name":"Jai","age":"28"},
{"id":"01","name":"Suresh","age":"28"}
]},
{"id":"02","invdate":"2014-07-24","name":"Hill",
"subGridData": [{
"id":"01","name":"Mani","age":"28"},
{"id":"01","name":"Raj","age":"28"},
{"id":"01","name":"Main","age":"28"}
]}
];
在这种情况下,
subGridData
的值将是object(项目数组),而不是string。Oleg请查看上面更新的代码。从db获取第一个列表工作正常,然后填充父网格和子网格。轮询操作后,子网格不工作。使用的代码如下var$mygrid=$(“#list11”);$mygrid.jqGrid(“addRowData”ID“,data);$mygrid.trigger(“reloadGrid”,[{current:true}]);–@krishnakumarsubbayian:我不清楚从server.php?getPollList返回的数据是哪种格式