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Jquery 条令收集Json响应问题_Jquery_Json_Ajax_Symfony_Doctrine Orm - Fatal编程技术网

Jquery 条令收集Json响应问题

Jquery 条令收集Json响应问题,jquery,json,ajax,symfony,doctrine-orm,Jquery,Json,Ajax,Symfony,Doctrine Orm,因此,我有和Ajax POST,他们在控制器中调用一个函数,重新调用json响应,如下所示: $images = $this->getEntityManager()->getRepository('AppBundle:Image')->findBy(array(),array(),5); $response = new JsonResponse(); $response->setData(array( 'images' =>

因此,我有和Ajax POST,他们在控制器中调用一个函数,重新调用json响应,如下所示:

    $images = $this->getEntityManager()->getRepository('AppBundle:Image')->findBy(array(),array(),5);
    $response = new JsonResponse();
    $response->setData(array(
        'images' => $images
    ));
    return $response;
我有五种元素,但都是空的。。。如下图所示:

例如,我从数组中的元素i返回一些属性,它可以工作:

$images = $this->getEntityManager()->getRepository('AppBundle:Image')->findBy(array(),array(),5);
$response = new JsonResponse();
$response->setData(array(
   'images' => $images[0]->getSlug()
));

return $response;

以下是简单的ajax代码:

$.ajax({
     method: 'POST',
     url: $("#scroll-down").attr("data-href"),
     success: function(response) {
          console.log(response);
     },
     error: function() {
          console.log(response);
     }
}).fail(function() {
     console.log(response);
});

在Symfony
JsonResponse
中,它主要是php函数的包装器
json\u encode

json_encode
不会对私有对象属性进行编码

<?php

class Test {
    private $a = null;
    public $b = 3;

    public function __construct($a) {
        $this->a = $a;
    }
}

$test = new Test(1);

echo json_encode($test);

对,条令ArrayCollection有一个名为$elemnts的私有属性。解决方案可以是使用适当的库来序列化对象,比如jms\u序列化程序。这个库使用反射,然后私有方法也将被序列化!