jquery ajax表单提交赢得';t绑定MVC4中的复杂模型
我有一个表单,我需要通过ajax提交,它正在提交,但没有绑定到模型 我的jquery源代码如下jquery ajax表单提交赢得';t绑定MVC4中的复杂模型,jquery,ajax,asp.net-mvc,asp.net-mvc-4,Jquery,Ajax,Asp.net Mvc,Asp.net Mvc 4,我有一个表单,我需要通过ajax提交,它正在提交,但没有绑定到模型 我的jquery源代码如下 function SubmitForm() { console.log($("#PackageSubscription").serialize()); $.ajax({ url: '/HelpDesk/CalculateCost', cache: false, processData: false, data: $("#PackageSubscription").ser
function SubmitForm() {
console.log($("#PackageSubscription").serialize());
$.ajax({
url: '/HelpDesk/CalculateCost',
cache: false,
processData: false,
data: $("#PackageSubscription").serialize(),
type: 'POST',
success: function (data) {
}
});
}
当我通过submit按钮使用标准mvc submit(同步)时,完全相同的表单绑定
有趣的是,控制台日志包含所有表单值,当我们同步提交表单时,它们完全相同(来自ajax调用的控制台日志字符串和来自fiddler请求检查器的表单值完全相同)
一些示例数据如下
MemberId=12345678
&SitePackges[0].SiteId=50
&SitePackges[0].SizeIndicator=2
&SitePackges[0].LstPackageDisplayItems[0].PackageId=4
&SitePackges[0].LstPackageDisplayItems[0].Name=PAT and Emergency Lighting
&SitePackges[0].LstPackageDisplayItems[0].IsSubscribed=True
&SitePackges[0].LstPackageDisplayItems[0].LastServiceDate=
&SitePackges[0].LstPackageDisplayItems[0].ProposedDate=
&SitePackges[0].LstPackageDisplayItems[1].PackageId=6
&SitePackges[0].LstPackageDisplayItems[1].Name=Fire Alarm and Extinguishers
&SitePackges[0].LstPackageDisplayItems[1].IsSubscribed=True
&SitePackges[0].LstPackageDisplayItems[1].LastServiceDate=
&SitePackges[0].LstPackageDisplayItems[1].ProposedDate=
我的viewmodel看起来像
public class PpmTypePackageSubscriptionModel
{
public int MemberId { get; set; }
public DateTime TimeStamp { get; set; }
public List<SitePackage> SitePackges { get; set; }
public double TotalCost { get; set; }
public PpmTypePackageSubscriptionModel()
{
SitePackges=new List<SitePackage>();
}
}
public class SitePackage
{
public int SiteId { get; set; }
public int SizeIndicator { get; set; }
public string Site { get; set; }
public List<PackageDisplayItem> LstPackageDisplayItems { get; set; }
public SitePackage()
{
LstPackageDisplayItems=new List<PackageDisplayItem>();
}
}
如果我理解正确,表单不会更新,因为您没有对从ajax响应接收到的数据进行任何处理 您应该将结果绑定到ajax success函数中。Ajax是异步的,因此数据是发布的,但响应不一定是立即的。当成功接收到响应(没有超时或连接丢失等)时,ajax调用转到success函数,并且响应数据存储在变量“data”中 尝试执行以下操作:
function SubmitForm() {
console.log($("#PackageSubscription").serialize());
$.ajax({
url: '/HelpDesk/CalculateCost',
cache: false,
processData: false,
data: $("#PackageSubscription").serialize(),
type: 'POST',
success: function (data) {
alert(data); // This will only show the response for you, use for debugging only
$("#MemberId").value(data.MemberId);
}
});
从ajax中删除processData:false。那么它肯定会与您的模型绑定。请阅读以下内容: processData(默认值:true) 类型:布尔型
默认情况下,作为对象传递到数据选项的数据(从技术上讲,是字符串以外的任何内容)将被处理并转换为查询字符串,符合默认内容类型“application/x-www-form-urlencoded”。如果要发送DOMDocument或其他未处理的数据,请将此选项设置为false。这可能是serialize()函数的问题 尝试改用JSON.stringify
<script type="text/javascript">
function OnBtnSubmitClick(s, e) {
var item1 = SecurityCode.GetText();
var item2 = SecurityCoderMnem.GetText();
var item3 = SecurityRegNum.GetText();
var item4 = SecurityIsin.GetText();
var item5 = document.getElementById("DocOrderSecurityOut_Id").value;
var item6 = document.getElementById("IsEdit").value;
var jsmodel = {
DocOrderSecurityOut: {
SecurityCode: item1,
SecurityCoderMnem: item2,
SecurityRegNum: item3,
SecurityIsin: item4,
Id: item5
},
IsEdit: item6
};
$.ajax({
url: '@Url.Action("AjaxForm", "DocOrderSecurityOut")',
data: JSON.stringify(jsmodel),
dataType: 'html',
contentType: "application/json; charset=utf-8",
type: "POST",
beforeSend: function () { loadingPanel.Show(); },
complete: function () { loadingPanel.Hide(); },
error: function (x, status, error) {
alert("Error code: " + x.status + '\n' +
"State: " + status + ". More info: " + error);
},
success: function (response) {
$("#container").html(response);
}
});
}
在Global.asax中:
ValueProviderFactories.Factories.Add(
new JsonValueProviderFactory());
请尝试从构造函数中删除
SitePackages
初始化。很抱歉,这没有任何区别。请使用[FromBody]
装饰控制器操作中的参数,如“public ActionResult ActionName([FromBody]PpmTypePackageSubscriptionModel value)@StephenMuecke谢谢。我希望它也能很好地工作,但我不明白它为什么会失败。是的,我已经重命名了模型,这不是问题。这可能是数据相关的问题吗?我的意思是,mvc模型绑定器在通过ajax发出请求时不会忽略某些字符或数据。正是因为这个原因,我添加了processData:false
,我将删除它,并且我确信在我添加该属性之前问题就已经存在。应该不会有任何区别(您甚至已经使用fiddler自己确认了)。如果您注释掉脚本并进行正常的提交,那么ajax提交也应该正常工作。@Rohit Arora已经尝试过了,没有什么区别
function SubmitForm() {
console.log($("#PackageSubscription").serialize());
$.ajax({
url: '/HelpDesk/CalculateCost',
cache: false,
processData: false,
data: $("#PackageSubscription").serialize(),
type: 'POST',
success: function (data) {
alert(data); // This will only show the response for you, use for debugging only
$("#MemberId").value(data.MemberId);
}
});
<script type="text/javascript">
function OnBtnSubmitClick(s, e) {
var item1 = SecurityCode.GetText();
var item2 = SecurityCoderMnem.GetText();
var item3 = SecurityRegNum.GetText();
var item4 = SecurityIsin.GetText();
var item5 = document.getElementById("DocOrderSecurityOut_Id").value;
var item6 = document.getElementById("IsEdit").value;
var jsmodel = {
DocOrderSecurityOut: {
SecurityCode: item1,
SecurityCoderMnem: item2,
SecurityRegNum: item3,
SecurityIsin: item4,
Id: item5
},
IsEdit: item6
};
$.ajax({
url: '@Url.Action("AjaxForm", "DocOrderSecurityOut")',
data: JSON.stringify(jsmodel),
dataType: 'html',
contentType: "application/json; charset=utf-8",
type: "POST",
beforeSend: function () { loadingPanel.Show(); },
complete: function () { loadingPanel.Hide(); },
error: function (x, status, error) {
alert("Error code: " + x.status + '\n' +
"State: " + status + ". More info: " + error);
},
success: function (response) {
$("#container").html(response);
}
});
}
[HttpPost]
public ActionResult AjaxForm(DocOrderSecurityOutViewModel model)
{
// magic
}
ValueProviderFactories.Factories.Add(
new JsonValueProviderFactory());