如何在数据帧列上使用fromJSON解析JSON?
我有以下data.frame,其中一列名为“json”,两行是json数据:如何在数据帧列上使用fromJSON解析JSON?,json,r,rjson,Json,R,Rjson,我有以下data.frame,其中一列名为“json”,两行是json数据: df <- data.frame(json = c('{"client":"ABC Company","totalUSD":7110.0000,"durationDays":731,"familySize":4,"assignmentType":"Long Term","homeLocation":"Australia","hostLocation":"United States","serviceName":"
df <- data.frame(json = c('{"client":"ABC Company","totalUSD":7110.0000,"durationDays":731,"familySize":4,"assignmentType":"Long Term","homeLocation":"Australia","hostLocation":"United States","serviceName":"Service ABC","homeLocationGeoLat":-25.274398,"homeLocationGeoLng":133.775136,"hostLocationGeoLat":37.09024,"hostLocationGeoLng":-95.712891}', '{"client":"ABC Company","totalUSD":7110.0000,"durationDays":731,"familySize":4,"assignmentType":"Long Term","homeLocation":"Australia","hostLocation":"United States","serviceName":"Service XYZ","homeLocationGeoLat":-25.274398,"homeLocationGeoLng":133.775136,"hostLocationGeoLat":37.09024,"hostLocationGeoLng":-95.712891}'))
df$json final您可能希望从本练习中得到一个结果数据帧,因此:
do.call(rbind.data.frame, lapply(df$json, rjson::fromJSON))
## client totalUSD durationDays familySize assignmentType homeLocation hostLocation serviceName homeLocationGeoLat
## 2 ABC Company 7110 731 4 Long Term Australia United States Service ABC -25.2744
## 21 ABC Company 7110 731 4 Long Term Australia United States Service XYZ -25.2744
## homeLocationGeoLng hostLocationGeoLat hostLocationGeoLng
## 2 133.7751 37.09024 -95.71289
## 21 133.7751 37.09024 -95.71289
完全相同的结果将来自:
do.call(rbind.data.frame, lapply(df$json, jsonlite::fromJSON))
do.call(rbind.data.frame, lapply(df$json, RJSONIO::fromJSON))
您可能希望从本练习中得到一个结果数据帧,因此:
do.call(rbind.data.frame, lapply(df$json, rjson::fromJSON))
## client totalUSD durationDays familySize assignmentType homeLocation hostLocation serviceName homeLocationGeoLat
## 2 ABC Company 7110 731 4 Long Term Australia United States Service ABC -25.2744
## 21 ABC Company 7110 731 4 Long Term Australia United States Service XYZ -25.2744
## homeLocationGeoLng hostLocationGeoLat hostLocationGeoLng
## 2 133.7751 37.09024 -95.71289
## 21 133.7751 37.09024 -95.71289
完全相同的结果将来自:
do.call(rbind.data.frame, lapply(df$json, jsonlite::fromJSON))
do.call(rbind.data.frame, lapply(df$json, RJSONIO::fromJSON))
loadNamespace(名称)中出错:没有名为“rjson”的包。您安装了它吗?只是编写库(rjson)不起作用。install.packages('rjson')现在可以工作了。谢谢:)我想你可能需要学习一下R和SO礼仪。是的!我正在努力:))loadNamespace(名称)中的错误:没有名为“rjson”的包。嗯,您安装了它吗?只是编写库(rjson)不起作用。install.packages('rjson')现在可以工作了。谢谢:)我想你可能需要学习一下R和SO礼仪。是的!我正在努力:))