如何在perl中将对象附加到JSON数组中?
我试图将该对象附加到json数组中,但结果显示为不同的格式。如果有人能告诉我正确的方法,我将不胜感激 这是我的密码:如何在perl中将对象附加到JSON数组中?,json,perl,Json,Perl,我试图将该对象附加到json数组中,但结果显示为不同的格式。如果有人能告诉我正确的方法,我将不胜感激 这是我的密码: sub create_release_text_file { my $result_path = shift; my %hshReleasebuild ; my @Releasebuild ; my $json = JSON->new->allow_nonref; my $relea
sub create_release_text_file
{
my $result_path = shift;
my %hshReleasebuild ;
my @Releasebuild ;
my $json = JSON->new->allow_nonref;
my $release_path = File::Spec->catfile($result_path, "release.txt");
$hshReleasebuild{"Build"} = $ARG_BUILD;
$hshReleasebuild{"Release"} = $ARG_RELEASE;
push(@Releasebuild,\%hshReleasebuild);
my $json_releasebuild = $json->encode(\@Releasebuild );
open RELEASE_FILE, ">>", $release_path or die $!;
print RELEASE_FILE $json_releasebuild;
close RELEASE_FILE;
}
结果表明:
[{"Release":"11.0","Build":"135"}][{"Release":"12.0","Build":"120"}] ...
但我想得到的结果是:
[{"Release":"11.0","Build":"135"},{"Release":"12.0","Build":"120"}, ...]
要添加到JSON文件中表示的数组,您需要首先实际获取该数组
my $json = do { local $/; <> };
my $releases = decode_json($json);
push @$releases, \%hshReleasebuild;
print encode_json($releases);
my$json=do{local$/;};
my$releases=decode_json($json);
推送@$releases,\%hshReleasebuild;
打印encode_json($releases);
(处理STDIN和STDOUT之外的文件句柄。)所以在调用
$json->encode()
之前修改@ReleaseBuild
的内容。你有什么版本的json
呢?@mob我正在使用json-support\u by\u pp;如果你要打开>
@AndyLester的文件,你永远不会得到正确的结果,你能告诉我怎么走吗?谢谢,谢谢ikegami,你太棒了!当我在每个对象中循环时,你能告诉我,我想附加一个额外的键值对吗?@Spongekyle Hashpants,$releases
是对“对象”(散列)引用数组的引用,因此,$\uuo->{foo}=$bar表示@$releases代码>哇,太简单了。非常感谢!