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Linq在新语句中获取实体的过程_Linq_C# 4.0_Linq To Entities_Wcf Ria Services - Fatal编程技术网

Linq在新语句中获取实体的过程

Linq在新语句中获取实体的过程,linq,c#-4.0,linq-to-entities,wcf-ria-services,Linq,C# 4.0,Linq To Entities,Wcf Ria Services,我尝试在WCF服务中使用类似的内容: 我有一张有经纬度的桌子。以及来自用户的位置。在查询中,我需要从用户到报价的距离,然后按此进行订购 private double Distanze(double LAT1, double LON1, double LAT2, double LON2) { double e = (3.1415926538 * LAT1 / 180); double f = (3.1415926538 * LON1 / 180); double g = (

我尝试在WCF服务中使用类似的内容:

我有一张有经纬度的桌子。以及来自用户的位置。在查询中,我需要从用户到报价的距离,然后按此进行订购

private double Distanze(double LAT1, double LON1, double LAT2, double LON2)
{
    double e = (3.1415926538 * LAT1 / 180);
    double f = (3.1415926538 * LON1 / 180);
    double g = (3.1415926538 * LAT2 / 180);
    double h = (3.1415926538 * LON2 / 180);
    double i = (Math.Cos(e) * Math.Cos(g) *
        Math.Cos(f) * Math.Cos(h) + Math.Cos(e) *
        Math.Sin(f) * Math.Cos(g) * Math.Sin(h) +
        Math.Sin(e) * Math.Sin(g));
    double j = (Math.Acos(i));
    double k = (6371 * j);
    return k;
}
在查询中:

public IQueryable<V1_Off_Offert> Get_myOffert()
{
    var User = GetCurrentPers_ID();

    if (User != 0)
    {
        double lat = GetCurrentPOS().LAT;
        double lon = GetCurrentPOS().LON;
        var query = from c in this.ObjectContext.C1_OFF_OFFERT
                    where c.C1_PERS_PERSON_ID == User
                    select new V1_Off_Offert()
                    {
                        ID = c.ID,

                        //......

                        LAT = (double)c.C1_ORT_GEO.LAT,
                        LON = (double)c.C1_ORT_GEO.LON,
                        //This it dosnt Work
                        Distanz = (double)Distanze((double)c.C1_ORT_GEO.LAT, (double)c.C1_ORT_GEO.LON, lat, lon),
                        Radius = (double)c.DISTANZ
                    };

        return query;
    }
    else return null;
}
public IQueryable Get\u myOffert()
{
var User=GetCurrentPers_ID();
如果(用户!=0)
{
双lat=GetCurrentPOS().lat;
双lon=GetCurrentPOS().lon;
var query=来自this.ObjectContext.C1\u OFFERT中的c
其中c.C1\u PERS\u PERSON\u ID==用户
选择新V1\u Offert()
{
ID=c.ID,
//......
纬度=(双)c.C1\u or\u GEO.LAT,
LON=(双)c.C1_或_GEO.LON,
//这不管用
Distanz=(双)Distanze((双)c.C1\u or\u GEO.LAT,(双)c.C1\u or\u GEO.LON,LAT,LON),
半径=(双)c.距离
};
返回查询;
}
否则返回null;
}

有没有办法实现这一点?

好的,我知道问题出在哪里了。LINQ to SQL正在尝试将
Distanze
转换为SQL。它不能,所以它死了。您需要在对数据库执行查询后进行投影。

我尝试以下方法:

public IQueryable<V1_Off_Offert> Get_myOffert()
    {

        var User = GetCurrentPers_ID();
        if (User != 0)
        {
            double lat = GetCurrentPOS().LAT;
            double lon = GetCurrentPOS().LON;
            var query = from c in this.ObjectContext.C1_OFF_OFFERT
                        where c.C1_PERS_PERSON_ID == User
                        select new V1_Off_Offert()
                        {
                            ID = c.ID,
                            Image = c.Image,
                            Start_Datum = c.VON,
                            End_Datum = c.BIS,
                            Name = c.C1_KEY_WORT.WORT,
                            Text = c.TEXT,
                            Preis = (decimal)c.PREIS != 0 ? (decimal)c.PREIS : 0,
                            WORT = c.C1_GRUP_GRUPPE.C1_KEY_WORT.WORT,
                            PERS_ID = (int)c.C1_PERS_PERSON_ID,
                            //COM_ID = (int)c.C1_COM_COMP_ID,
                            EH_ID = c.C1_OFF_EINHEIT_ID,
                            LAT = (double)c.C1_ORT_GEO.LAT,
                            LON = (double)c.C1_ORT_GEO.LON,

                            //Distanz = (double)Distanze((double)c.C1_ORT_GEO.LAT, (double)c.C1_ORT_GEO.LON, lat, lon),
                            Radius = (double)c.DISTANZ

                            //LAT = c.C1_ORT_GEO.LAT != null ? (double)c.C1_ORT_GEO.LAT : 0
                        };
            foreach (V1_Off_Offert T in query)
            {
                T.Distanz = Distanze(T.LAT, T.LON, lat, lon);                    
            }



        return query;

            }
        else return null;
    }
有没有办法使用第一种方法 也许是lambda的表达。
但将foreach的结果放入查询中并不是那么优雅

请纠正你问题中的拼写。这是对任何试图帮助你的人的侮辱。你能发布完整的例外消息吗??你只给了我们一个小片段——而且最重要的部分丢失了……你可能想考虑使用<代码> Madi.Pix>代码>,如果你写了<代码>(3.1415926538×x/180),你的代码将更可读;代码>as
转换器半径(x)我不知道什么是
6371
,但如果你能为它提供一些背景,你未来的自己会感谢你的(评论是一种方式,但它们只是)。好的,我现在就开始。但它也必须能够在LinQ中使用它。这是一个奇怪的要求。告诉我为什么。
foreach (V1_Off_Offert T in query)
            {
                T.Distanz = Distanze(T.LAT, T.LON, lat, lon);                    
            }