Linq EFCore 2.2按总和和日期差异分组

我正在尝试将下面的SQL转换为EF核心查询，并且收到了GroupBy和Sum将在本地计算的警告。目前是否有编写此文件的方法将其完全转换为SQL

SELECT UserId, ST.StatusId, SUM(DATEDIFF(MINUTE, StartDate, ISNULL(EndDate,GETDATE()))) AS Time
FROM StatusTransaction ST
WHERE
    TeamManagerId = 1
    AND StartDate >= N'01-01-2019'
    AND ISNULL(EndDate,GETDATE()) <= N'01-02-2019'
GROUP BY UserId, ST.StatusId
ORDER BY UserId

选择UserId、ST.StatusId、SUM（DATEDIFF（MINUTE、StartDate、ISNULL（EndDate、GETDATE（））作为时间
来自statusst事务
哪里
TeamManagerId=1
开始日期>=N'01-01-2019'
首先，EF核心仍然不支持转换
TimeSpan
操作，并且
DateTime
差异产生
TimeSpan
，因此
EF.Functions.DateDiff
方法是正确的选择

其次，它仍然只能在简单的成员访问器表达式上转换
GroupBy
聚合。因此，您必须在
之前选择
GroupBy
表达式：

var query = context
    .Where(st => st.TeamManagerId == tmId
        && st.StartDate >= dateFrom
        && (st.EndDate ?? DateTime.Now) <= dateTo
    )
    .Select(st => new
    {
        st.UserId,
        st.StatusId,
        Time = EF.Functions.DateDiffMinute(st.StartDate, st.EndDate ?? DateTime.Now)
    })
    .GroupBy(st => new { st.UserId, st.StatusId })
    .Select(g => new
    {
        g.Key.UserId,
        g.Key.StatusId,
        Time = g.Sum(st => st.Time)
    });

var query = context
    .Where(st => st.TeamManagerId == tmId
        && st.StartDate >= dateFrom
        && (st.EndDate ?? DateTime.Now) <= dateTo
    )
    .Select(st => new
    {
        st.UserId,
        st.StatusId,
        Time = EF.Functions.DateDiffMinute(st.StartDate, st.EndDate ?? DateTime.Now)
    })
    .GroupBy(st => new { st.UserId, st.StatusId })
    .Select(g => new
    {
        g.Key.UserId,
        g.Key.StatusId,
        Time = g.Sum(st => st.Time)
    });

var query = context
    .Where(st => st.TeamManagerId == tmId
        && st.StartDate >= dateFrom
        && (st.EndDate ?? DateTime.Now) <= dateTo
    )
    .GroupBy(st => new { st.UserId, st.StatusId }, st => new
    {
        Time = EF.Functions.DateDiffMinute(st.StartDate, st.EndDate ?? DateTime.Now)
    })
    .Select(g => new
    {
        g.Key.UserId,
        g.Key.StatusId,
        Time = g.Sum(st => st.Time)
    });