如何知道Linux系统中的哪个用户已解锁？

我想知道用户通过Linux的登录GUI在系统中解锁自己时的用户名。我已经检查了

/etc/pam.d/gdm密码

。据我所知，

unlock

和

lock

操作与

gdm password

相关。这是我的

gdm密码

文件，如下所示

#%PAM-1.0
auth    requisite       pam_nologin.so
auth    required    pam_succeed_if.so user != root quiet_success

@include common-auth
auth    optional        pam_gnome_keyring.so
account optional  pam_exec.so seteuid /trigger account
session optional  pam_exec.so seteuid /trigger session
@include common-account
# SELinux needs to be the first session rule. This ensures that any 
# lingering context has been cleared. Without this it is possible 
# that a module could execute code in the wrong domain.
session [success=ok ignore=ignore module_unknown=ignore default=bad]        pam_selinux.so close
session required        pam_loginuid.so
# SELinux needs to intervene at login time to ensure that the process
# starts in the proper default security context. Only sessions which are
# intended to run in the user's context should be run after this.
session [success=ok ignore=ignore module_unknown=ignore default=bad]        pam_selinux.so open
session optional        pam_keyinit.so force revoke
session required        pam_limits.so
session required        pam_env.so readenv=1
session required        pam_env.so readenv=1 envfile=/etc/default/locale
@include common-session
session optional        pam_gnome_keyring.so auto_start
@include common-password

这是我的bash脚本：

#!/bin/bash
id=$(/usr/bin/cat /proc/self/sessionid)
#echo "$date [$1] $PAM_USER $PAM_TYPE $id" >> /var/log/test.log
name=$(/usr/bin/loginctl show-session $id | /usr/bin/grep Name= | /usr/bin/cut -d = -f 2)
if [ "$PAM_TYPE" == "account" ] && [[ -v id ]] && [ "$name" == "$PAM_USER" ];then
    echo "$date $PAM_USER unlocked" >> /var/log/actions.log
#   echo "$(/usr/bin/loginctl show-session $id)" >> /var/log/details.log
elif  [ "$PAM_TYPE" == "open_session" ];then
    echo "$date $PAM_USER logged in" >> /var/log/actions.log
elif  [ "$PAM_TYPE" == "close_session" ];then
    echo "$date $PAM_USER logged out" >> /var/log/actions.log
fi

---

解锁时，屏幕上会出现一个错误，如

/trigger failed:exit code 2

。我该怎么办？当用户解锁时，我只想在文件中看到他的名字。就是这样。

当您在没有参数的情况下执行

loginctl

时，它会显示“c2”。如果我运行

loginctl show session c2

，它将返回正确的输出。不知道为什么

/proc/self/sessionid

只返回2而不是c2。