Mongodb 如何在golang的mongo中将bson.M元素列表合并为单个bson.M?
} 同一个密钥的所有操作都需要追加。提前感谢Mongodb 如何在golang的mongo中将bson.M元素列表合并为单个bson.M?,mongodb,go,bson,mgo,Mongodb,Go,Bson,Mgo,} 同一个密钥的所有操作都需要追加。提前感谢 I want the in this format : bson.M{"$inc": bson.M{"Google.ab.Value": 1, "AB.Value.to": 2}} 这就是您可以尝试的为什么键“AB.Value.to”增加了2?这是一种类型,还是因为它是第二个添加的类型? I want the in this format : bson.M{"$inc": bson.M{"Google.ab.Value": 1, "AB.V
I want the in this format :
bson.M{"$inc": bson.M{"Google.ab.Value": 1, "AB.Value.to": 2}}
这就是您可以尝试的为什么键“AB.Value.to”增加了2?这是一种类型,还是因为它是第二个添加的类型?
I want the in this format :
bson.M{"$inc": bson.M{"Google.ab.Value": 1, "AB.Value.to": 2}}
func (o *MongoOps) AddToBsonMapElement(lstMap map[string]interface{}, Operation string, key string, value interface{}) (result map[string]interface{}) {
status, msg := EmptyStructCheck(o)
if status == true {
LogError(msg)
panic(msg)
}
if Operation == "$addToSetEach" {
if _, ok := lstMap["$addToSet"]; ok {
childmap := lstMap["$addToSet"]
subchildmap := childmap.(map[string]interface{})
var val map[string]interface{}
val = make(map[string]interface{})
val["$each"] = value
subchildmap[key] = val
lstMap["$addToSet"] = subchildmap
} else {
lstMap["$addToSet"] = bson.M{key: bson.M{"$each": value}}
}
fmt.Println(reflect.TypeOf(lstMap))
} else if _, ok := lstMap[Operation]; ok {
childmap := lstMap[Operation]
subchildmap := childmap.(map[string]interface{})
subchildmap[key] = value
lstMap[Operation] = subchildmap
} else {
childmap := make(map[string]interface{}, 0)
childmap[key] = value
lstMap[Operation] = childmap
}
return lstMap
}