Ms access 检查表中的字段是否具有空格或逗号-MS访问权限

我有一个名为FinalForgotten的表，它只包含一个名为aname的字段。这个领域要么像史密斯·约翰，要么像史密斯·约翰。所以姓和名都在同一个字段中，并由空格或逗号分隔。防御字段包含三个字段：名字、姓氏、中间首字母。first_name字段将包含与aname字段中的数据完全匹配的数据（例如John）。last_name字段将包含与aname字段中的一段数据完全匹配的数据（例如Smith）。我正在尝试将所有带有中间首字母的FinalForgotten aname记录放入一个新表中（例如Smith、John S）。防御表就是这个中间的首字母

这将有助于：

SELECT left([aname],InStr(1,[aname],",")-1) & " "& right([aname],Len(aname)-InStr(1,[aname],",")) & " "& summary_judgment.middle_initial AS fullnameINTO FinalForgottenWithMiddle FROM FinalForgotten INNER JOIN summary_judgment ON((left(FinalForgotten.aname,InStr(1,FinalForgotten.[aname],",")-1))=summary_judgment.last_name) AND((right(FinalForgotten.aname,Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname],","))=summary_judgment.first_name));

但如果FinalForgotten包含一个没有逗号的字段，它将返回“invalid procedure call”，如： 史密斯·约翰

因此，为了解决这个问题，我尝试考虑字段中是否有逗号：

SELECT left([aname], IIF(instr([aname], ",") = 0, InStr(1,[aname]," ")-1),InStr(1,[aname],",")-1)  &  ", "  & right([aname], IIF(instr([aname], ",") = 0,Len(aname)-InStr(1,[aname]," "),Len(aname)-InStr(1,[aname],",") &  " " & defense_final.middle_initial AS fullname INTO FinalForgottenWithMiddle
FROM FinalForgotten INNER JOIN defense_final ON 
((right(FinalForgotten.aname,IIF(instr([aname], ",") = 0,Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname]," ")),Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname],","))=defense_final.first_name)) 
AND 
((left(FinalForgotten.aname,,IIF(instr([aname], ",") = 0,InStr(1,FinalForgotten.[aname]," ")-1)),InStr(1,FinalForgotten.[aname],",")-1))=defense_final.last_name);

这给了我一个“缺少运算符语法”错误，并突出显示单词AS

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感谢您的回复。

似乎少了不少括号

SELECT left(
      [aname], 
      IIF(instr([aname], ",") = 0,
        InStr(1,[aname]," ")-1,
        InStr(1,[aname],",")-1
        ) 
      )
    &  ", "  & 
    right(
       [aname], 
       IIF(instr([aname], ",") = 0,
         Len(aname)-InStr(1,[aname]," "),
         Len(aname)-InStr(1,[aname],",") 
         )
        )
     &  " " & 
    defense_final.middle_initial AS fullname 
INTO FinalForgottenWithMiddle
FROM FinalForgotten
INNER JOIN defense_final 
ON 

    right(FinalForgotten.aname,
     IIF(instr([aname], ",") = 0,
     Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname]," "),
     Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname],",")
      )
     )=defense_final.first_name

AND 

   left(FinalForgotten.aname,
    IIF(instr([aname], ",") = 0,
      InStr(1,FinalForgotten.[aname]," ")-1,
      InStr(1,FinalForgotten.[aname],",")-1
        )
    )=defense_final.last_name

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谢谢，我也喜欢你提出问题的方式。