如何正确计算日期时间(结束日期和开始日期之间的差异)-mysql
我正在mysql中使用。我创建了表“Sikcness”,并添加了一条记录:如何正确计算日期时间(结束日期和开始日期之间的差异)-mysql,mysql,datetime,difference,Mysql,Datetime,Difference,我正在mysql中使用。我创建了表“Sikcness”,并添加了一条记录: +--------+---------+---------+-------------+--------+----------+ | Id_SICK|ID_WORKER| BEGIN_DATE | END_DATE | +--------+---------+---------+----------+------------+---------+ | 1 | 1
+--------+---------+---------+-------------+--------+----------+
| Id_SICK|ID_WORKER| BEGIN_DATE | END_DATE |
+--------+---------+---------+----------+------------+---------+
| 1 | 1 |2019-03-18 07:00:00 |2019-03-20 15:00:00 |
+--------+---------+--------+------------+----------+----------+
然后我想通过以下命令计算时间(结束日期列和开始日期列之间的时间差):
SELECT SEC_TO_TIME(SUM(TIME_TO_SEC(Sickness.END_DATE) - TIME_TO_SEC(Sickness.BEGIN_DATE))) AS 'SICKNESS TIME' FROM Sickness WHERE ID_WORKER = 1
但我只有这个结果(这是不正确的):
该命令应按如下方式计算:
+---------+-------------+--------+----------+
| BEGIN_DATE | END_DATE |
+---------+----------+------------+---------+
|2019-03-18 07:00:00 |2019-03-18 15:00:00 |
+--------+------------+----------+----------+
|2019-03-19 07:00:00 |2019-03-19 15:00:00 |
+--------+------------+----------+----------+
|2019-03-20 07:00:00 |2019-03-20 15:00:00 |
+--------+------------+----------+----------+
那就对了:
SICKNESS TIME
24:00:00
我应该编写什么样的mysql查询?有什么想法吗?问候。小时差应乘以天数差:
mysql> SELECT SEC_TO_TIME(SUM((DATEDIFF(end_date, begin_date) + 1) * (TIME_TO_SEC(END_DATE) - TIME_TO_SEC(BEGIN_DATE)))) AS 'SICKNESS TIME' FROM Sickness WHERE ID_WORKER = 1;
+---------------+
| SICKNESS TIME |
+---------------+
| 24:00:00 |
+---------------+
1 row in set (0.00 sec)
另一个时间\格式的查询:
mysql> select time_format(SUM((datediff(end_date, begin_date) + 1) * (time(end_date) - time(begin_date))), '%H:%i:%s') as 'SICKNESS TIME' from Sickness where id_worker = 1;
+---------------+
| SICKNESS TIME |
+---------------+
| 24:00:00 |
+---------------+
1 row in set (0.00 sec)
您可以在上尝试此查询,因此,您需要按如下方式计算:
+---------+-------------+--------+----------+
| BEGIN_DATE | END_DATE |
+---------+----------+------------+---------+
|2019-03-18 07:00:00 |2019-03-18 15:00:00 |
+--------+------------+----------+----------+
|2019-03-19 07:00:00 |2019-03-19 15:00:00 |
+--------+------------+----------+----------+
|2019-03-20 07:00:00 |2019-03-20 15:00:00 |
+--------+------------+----------+----------+
SELECT
TIMESTAMPDIFF(HOUR, begin_date, CONCAT(DATE(begin_date), ' 15:00:00')) +
(TIMESTAMPDIFF(DAY, begin_date, end_date) - 1) * 8 +
TIMESTAMPDIFF(HOUR, CONCAT(DATE(end_date), ' 07:00:00'), end_date) AS time
FROM test
WHERE worker = 1;
这是我用这个命令做的,但是它显示了太多的=56:00:00。我需要这样的查询,我在topNo difference中描述过。对不起:(24:00:00是首选结果吗?是的,这对我最有帮助。非常感谢你的帮助!)