使用多个连接编写MySQL语句

我有4张桌子，它们是：

job, community, state, and region.  

其结构如下：

job:
columns:
  id
  community_id
relations:
  community:  local_key: community_id, foreign_key: id

community:
columns:
  id
  state_id
relations: 
  state: local_key: state_id, foreign_key: id

state:
columns:
  id
  name
  region_id
relations:
  region: local_key: region_id, foreign_key: id

region:
columns:
  id
  name

现在，我需要一个查询，它将：

get all the jobs with matching communities: i.e.: j.community_id = c.id

then, from those matches, get all of the jobs in communities with a state region_id = "1"

我做得很好，拉州，但我被困在试图拉该地区。我走了这么远：

SELECT j.id
FROM job j
INNER JOIN community c
ON j.community_id = c.id
WHERE c.state_id = 35

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我甚至不确定我的表是否正确设置以检索此信息。如果能帮我渡过难关，我将不胜感激

试试这个，我想这正是你想要的

SELECT
    r.name AS regionname,
    s.name AS statename
FROM
    job j
LEFT JOIN
    community c ON c.id = j.community_id
LEFT JOIN
    state s ON s.id = c.state_id
LEFT JOIN
    region r ON r.id = s.region_id
WHERE
    r.id = 1

---

就这样！非常感谢你！很高兴它对你有用，关于清晰数据库结构的问题+1