Mysql 仅从两个表查询中选择顶部结果

这是我的两张桌子：
歌曲：

投票：

+--------+--------+
| SongID | UserID |
+--------+--------+
|   3278 |     71 |
|   3278 |     72 |
|   3279 |     71 |
+--------+--------+

我试图计算

投票数

表中的条目数（对于每个唯一的

SongID

），并返回包含最多的条目的

SongDeviceID

这就是我到目前为止所做的：

SELECT Songs.SongDeviceID, COUNT(*) FROM Votes INNER JOIN Songs ON Votes.SongID = Songs.SongId GROUP BY Votes.SongID, Songs.SongDeviceID ORDER BY count(*) DESC

返回：

+---------------------+----------+
|    SongDeviceID     | Count(*) |
+---------------------+----------+
| 1079287588763212246 |        2 |
| 1079287588763212221 |        1 |
+---------------------+----------+

更新： 查询已更新，以获取SongDeviceID，但我仍然需要帮助，只返回第一行。

第一行

select top 1
    S.SongDeviceID, COUNT(distinct V.UserID) as 'UserVotes'
from
   Songs as S
join 
  Votes as V on V.SongID = S.SongID
group by
   S.SongDeviceID
order by
  UserVotes DESC

SELECT  SongID,COUNT(*) from votes GROUP BY SongID order by count(*) DESC LIMIT 1

然后你想要歌曲设备名

SELECT SongID,COUNT(*),SongDeviceID
from
  votes 
left join 
   Songs on votes.songid = song.songid
GROUP BY
   SongID 
order by 
   count(*) DESC LIMIT 1

试试这个

   SELECT Songs.SongDeviceID, COUNT(*) FROM Votes INNER JOIN Songs ON Votes.
    SongID =  Songs.SongId GROUP BY Votes.SongID, Songs.SongDeviceID ORDER BY count(*) 
    DESC LIMIT 1

---

您不能使用订单计数（*）desc limit by 1

您的SQL语法有错误；检查与您的MySQL服务器版本对应的手册，以了解第1行“by 1”附近使用的语法是否正确
您的SQL语法有错误；检查与您的MySQL服务器版本对应的手册，以了解在“1 S”附近使用的语法是否正确。SongDeviceID，COUNT（不同的V.UserID）作为歌曲中的“用户投票”，S在第1行加入V
   SELECT Songs.SongDeviceID, COUNT(*) FROM Votes INNER JOIN Songs ON Votes.
    SongID =  Songs.SongId GROUP BY Votes.SongID, Songs.SongDeviceID ORDER BY count(*) 
    DESC LIMIT 1