Mysql 表中最近的条目以一年为间隔

使用以下SQLFIDLE，我将如何使用前面查询中的案例陈述查找

2012-04-1

和

2012-03-31

之间的最近付款 我试过这个：

max(case when py.pay_date >= STR_TO_DATE(CONCAT(2012, '-04-01'),'%Y-%m-%d') and py.pay_date <=  STR_TO_DATE(CONCAT(2012, '-03-31'), '%Y-%m-%d') + interval 1 year  then py.amount end) CURRENT_PAY 

---

max（当py.pay\u date>=STR\u TO\u date（CONCAT（2012，-04-01'），“%Y-%m-%d”）和py.pay\u date时，该条件属于
WHERE
子句中，而不是
max（）
聚合中的
案例
，该条件通过在
上加入子查询来获取每个
人员的最新付款（付款日期），个人id

SELECT payment.* 
FROM 
  payment
  JOIN (
    SELECT MAX(pay_date) AS pay_date, person_id 
    FROM payment 
    WHERE pay_date BETWEEN '2012-04-01' AND DATE_ADD('2012-03-31', INTERVAL 1 YEAR)
    GROUP BY person_id
  ) maxp ON payment.person_id = maxp.person_id AND payment.pay_date = maxp.pay_date
  

select p.name,
  v.v_name,
  sum(case when Month(py.pay_date) = 4 then py.amount end) april_amount,

   (case when max(py.pay_date)and month(py.pay_date)= 4 then py.amount else 0 end) max_pay_april,

   sum(case 
        when Month(py.pay_date) = Month(curdate())
        then py.amount end) current_month_amount,
   sum(case 
        when Month(py.pay_date) = Month(curdate())-1
        then py.amount end) previous_month_amount,
   maxp.pay_date AS last_pay_date,
   maxp.amount AS last_pay_amount
from persons p
left join vehicle v
  on p.id = v.person_veh
left join payment py
  on p.id = py.person_id
/* LEFT JOIN against the subquery: */
left join (
   SELECT MAX(pay_date) AS pay_date, amount, person_id 
      FROM payment 
      WHERE pay_date BETWEEN '2012-04-01' AND DATE_ADD('2012-03-31', INTERVAL 1 YEAR)
      GROUP BY person_id, amount
    ) maxp ON maxp.person_id = p.id

group by p.name,
  v.v_name

这是您表中已更正的ID（因为其中有15个）。这将返回记录18，用于
2013-03-28

更新
在看到正确的SQL FIDLE…以将此查询的结果合并到现有查询中后，您可以将其作为
p.id
上的子查询进行
LEFT JOIN

SELECT payment.* 
FROM 
  payment
  JOIN (
    SELECT MAX(pay_date) AS pay_date, person_id 
    FROM payment 
    WHERE pay_date BETWEEN '2012-04-01' AND DATE_ADD('2012-03-31', INTERVAL 1 YEAR)
    GROUP BY person_id
  ) maxp ON payment.person_id = maxp.person_id AND payment.pay_date = maxp.pay_date
  

select p.name,
  v.v_name,
  sum(case when Month(py.pay_date) = 4 then py.amount end) april_amount,

   (case when max(py.pay_date)and month(py.pay_date)= 4 then py.amount else 0 end) max_pay_april,

   sum(case 
        when Month(py.pay_date) = Month(curdate())
        then py.amount end) current_month_amount,
   sum(case 
        when Month(py.pay_date) = Month(curdate())-1
        then py.amount end) previous_month_amount,
   maxp.pay_date AS last_pay_date,
   maxp.amount AS last_pay_amount
from persons p
left join vehicle v
  on p.id = v.person_veh
left join payment py
  on p.id = py.person_id
/* LEFT JOIN against the subquery: */
left join (
   SELECT MAX(pay_date) AS pay_date, amount, person_id 
      FROM payment 
      WHERE pay_date BETWEEN '2012-04-01' AND DATE_ADD('2012-03-31', INTERVAL 1 YEAR)
      GROUP BY person_id, amount
    ) maxp ON maxp.person_id = p.id

group by p.name,
  v.v_name

不，我得到的日期是正确的，不是吗>=3月31日，我错过了+间隔1年…哇，那么..我如何将其与其他查询一起包含？将其插入您的sqlfiddle。它返回记录15，2013年3月28日。如果您希望日期介于明年4月1日和3月31日之间，为什么您希望结果为记录12？@dames，您如何将其包含在查询中还有什么问题吗？看起来好像我们在看两个不同的fiddle@dames，所以你试图将支付日期合并到该fiddle的查询中？