Mysql 嵌套查询返回值

我有一张这样的表格

order\u details

 id |  SKU  |  quantity_purchased | discount_price
---------------------------------------------------
1   | abc   |   1                 |     10.0
2   | abc   |   90                |     00
2   | abc   |   9                 |     00
3   | xyz   |   1                 |     50.0
3   | xyz   |   2                 |     50.0
4   | xyz   |   100               |     00
4   | xyz   |   100               |     00
-----------------------------------------------

我的问题是

select 
(select sum(quantity_purchased)  from order_details where discount_price > 0.00) as qty_discount,
(select sum(quantity_purchased)  from order_details where discount_price = 0.00)as qty_original,
sku
from order_details
GROUP BY sku

我要求的成绩是

  SKU   |  quantity_original | quantity_discount
---------------------------------------------------
 abc    |   1                 |     99
 xyz    |   3                 |     200
-----------------------------------------------

也就是说，在计算之后，我需要为相同的

sku

设置两列

我无法建立逻辑，我已尝试在嵌套查询中使用

groupby

，但不起作用。。。 非常感谢您的帮助。。 谢谢

更新： 试图通过这个来做，但还是失败了

select 
(select sum(quantity_purchased)  from order_details where discount_price > 0.00 ) as qty_discount,
(select sum(quantity_purchased)  from order_details where discount_price = 0.00 )as qty_original,
sku
from order_details
where sku = (select distinct sku from order_details)
GROUP BY sku

---

您可以为此使用

条件聚合

：

select sku, 
       sum(case when discount_price != 0 then quantity_purchased 
                else 0 
           end) quantity_original,
       sum(case when discount_price = 0 then quantity_purchased 
                else 0 
           end) quantity_discount
from order_details
group by sku

---

---

+1、太棒了……万分感谢，你让我当了“每日老板”……有一件事，看起来你已经交换了列名（原来的列名已经打折了），但这不是问题，你有你的逻辑，感谢万分……你真的帮了大忙。。。

Results:

| SKU | quantity_original | quantity_discount |
|-----|-------------------|-------------------|
| abc |                 1 |                99 |
| xyz |                 3 |               200 |