Mysql 加入查询的问题

我在这个查询中遇到了错误。 我不知道这是怎么回事。 我们将不胜感激

SELECT Email, UserID, FirstName, LastName,
count(*) as userTextCount FROM user LEFT JOIN posts ON posts.PostedAsId = user.UserID and
PostedAs = 'USER' and PostType = 'text',
count(*) as userMediaCount FROM user LEFT JOIN posts ON posts.PostedAsId = user.UserID and
PostedAs = 'USER' and PostType = 'media'
WHERE 1
GROUP BY Email, UserID, FirstName, LastName

错误：

#1064 - You have an error in your SQL syntax; 
MySQL server version for the right syntax to use near 'count(*) as userMediaCount FROM
user LEFT JOIN posts ON posts.PostedAsId = user.' at line 3

用户表包含：Email、UserId、FirstName、LastName和posts表包含所有帖子，我需要按特定用户统计帖子

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谢谢。

您可以尝试使用条件计数，它可以是这样的

SELECT Email, UserID, FirstName, LastName,
       SUM(CASE WHEN PostedAs = 'USER' and PostType = 'text' THEN 1 ELSE 0) userTextCount,
       SUM(CASE WHEN PostedAs = 'USER' and PostType = 'media' THEN 1 ELSE 0) userMediaCount,
  FROM user u LEFT JOIN posts p
    ON p.PostedAsId = u.UserID 
 GROUP BY Email, UserID, FirstName, LastName

或

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你可以试试这个，它会给你一行和postType媒体，另一行和postType文本，你可以在你的业务层处理它们

SELECT Email, UserID, FirstName, LastName, PostType, count(PostType)
FROM user LEFT JOIN posts ON posts.PostedAsId = user.UserID 
WHERE PostedAs = 'USER' and PostType = 'media' OR  PostType = 'text'
GROUP BY Email, UserID, FirstName, LastName

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你应该告诉我们你到底需要什么。也许这个查询将是一个开始。

发布更多详细信息、表结构、错误、数据…编辑了问题…因此这是无效的基本语法，原因很多。我认为第一步需要阅读一篇关于查询语法的参考文献。你在这里做了什么？这真是一团糟。等等，你是说你知道OP想要完成什么吗？@user2696691有用吗？你的问题需要更多的帮助吗？

SELECT Email, UserID, FirstName, LastName, PostType, count(PostType)
FROM user LEFT JOIN posts ON posts.PostedAsId = user.UserID 
WHERE PostedAs = 'USER' and PostType = 'media' OR  PostType = 'text'
GROUP BY Email, UserID, FirstName, LastName

SELECT
    Email,
    UserID,
    FirstName,
    LastName,
    PostedAs,
    PostType
FROM
    user
    LEFT JOIN posts ON posts.PostedAsId = user.UserID
WHERE
    PostedAs = 'USER'
    AND PostType IN ('text', 'media')