Mysql 得分最高的最近日期

我有下面的表格定义

CREATE TABLE IF NOT EXISTS ranking (  
    user_id int(11) unsigned NOT NULL, 
    create_date date NOT NULL,  
    score double(8,2),
    PRIMARY KEY (user_id, create_date)
)

insert into ranking (user_id, create_date, score) values  
    (1, '2017-03-01', 100),  
    (1, '2017-03-02',  90),  
    (1, '2017-03-03',  80),  
    (1, '2017-03-04', 100), 
    (1, '2017-03-05',  90),  
    (2, '2017-03-01',  90),  
    (2, '2017-03-02',  80),  
    (2, '2017-03-03', 100),  
    (2, '2017-03-5', 100),  
    (3, '2017-03-01',  80),  
    (3, '2017-03-02', 100),  
    (3, '2017-03-03',  90),  
    (3, '2017-03-6', 100);

select * from ranking;  
    user_id | create_date | score   
          1 | 2017-03-01  |   100  
          1 | 2017-03-02  |    90   
          1 | 2017-03-03  |    80  
          1 | 2017-03-04  |   100   
          1 | 2017-03-05  |    90  
          2 | 2017-03-01  |    90   
          2 | 2017-03-02  |    80   
          2 | 2017-03-03  |   100   
          2 | 2017-03-05  |   100   
          3 | 2017-03-01  |    80   
          3 | 2017-03-02  |   100   
          3 | 2017-03-03  |    90   
          3 | 2017-03-06  |   100  

我想要的是，对于每个用户id，获取得分最大的最近创建日期。例如，在上面的示例中，对于用户_id=1，当create_date=2017-03-01和create_date=2017-03-04时，最大分数为100，但我只想要具有最大分数的最近日期，即create_date=2017-03-04和score=100。查询结果如下：

user_id | create_date | score   
      1 | 2017-03-04  |   100   
      2 | 2017-03-05  |   100  
      3 | 2017-03-06  |   100  

下面是我的解决方案，它返回了预期的结果，但我相信存在更好的解决方案

SELECT a.* from   
(  
    SELECT s1.user_id , s1.create_date, s1.score FROM ranking AS s1   
    INNER JOIN  
    (SELECT user_id , FORMAT(max(score), 0) as best_score FROM ranking GROUP BY user_id ) AS s2  
    ON s1.user_id = s2.user_id AND s1.score = s2.best_score  
) a   
NATURAL LEFT JOIN   
(  
    SELECT s1.user_id , s1.create_date, s1.score FROM ranking AS s1   
    INNER JOIN   
    (  
        SELECT user_id , create_date, score FROM ranking  
    ) s2  
    WHERE s1.user_id = s2.user_id AND s1.score = s2.score AND s1.create_date < s2.create_date  
) b  
WHERE b.user_id IS NULL;  

有人能提供更好的解决方案吗？谢谢。

试试这个：

select user_id, max(create_date),max(score) from ranking GROUP BY user_id

结果:

1   2017-03-04  100.00
2   2017-03-05  100.00
3   2017-03-06  100.00

1   2017-03-04  100
2   2017-03-05  100
3   2017-03-06  100

或

结果:

1   2017-03-04  100.00
2   2017-03-05  100.00
3   2017-03-06  100.00

1   2017-03-04  100
2   2017-03-05  100
3   2017-03-06  100

输出：

此处演示：

请尝试此查询-

SELECT r1.* FROM ranking r1
  JOIN (SELECT user_id, MAX(score) max_score FROM ranking GROUP BY user_id) r2
    ON r1.user_id = r2.user_id AND r1.score = r2.max_score
  JOIN (SELECT user_id, score, MAX(create_date) max_create_date FROM ranking GROUP BY user_id, score) r3
    ON r1.user_id = r3.user_id AND r1.score = r3.score AND r1.create_date = r3.max_create_date;

---

@蒂姆：我只是在最近的一次约会后以最高分的成绩跟在后面。你也得到了一个很好的答案。。你知道我有时从你编写代码的方式中学到了什么。@tim你的导师。

1   04-Mar-17   100
2   05-Mar-17   100
3   06-Mar-17   100