Mysql 如何从表1中联接2个sql(sum(表1)和count(表2))并按日期分组?
第一个表和第二个表按id_进行关联 在表1中查询为“销售表” 结果1 表2中查询为“明细销售表” 结果2 我想要的是这个 这就是我尝试过的Mysql 如何从表1中联接2个sql(sum(表1)和count(表2))并按日期分组?,mysql,sql,Mysql,Sql,第一个表和第二个表按id_进行关联 在表1中查询为“销售表” 结果1 表2中查询为“明细销售表” 结果2 我想要的是这个 这就是我尝试过的 select bt.tanggal as date_sold, count(bt.kd_op_beli_tunai) as quantity_id_sold, sum(rbt.harga_satuan * rbt.jumlah) as total_sold from t_pembelian_tunai as bt, t_rinci_beli_
select bt.tanggal as date_sold, count(bt.kd_op_beli_tunai) as quantity_id_sold, sum(rbt.harga_satuan * rbt.jumlah) as total_sold
from t_pembelian_tunai as bt, t_rinci_beli_tunai as rbt
where bt.kd_op_beli_tunai = rbt.kd_op_beli_tunai
GROUP by tanggal
ORDER by tanggal DESC
结果是
您可以尝试此查询
SELECT bt.tanggal as date_sold,bt.quantity_id_sold,rbt.total_sold
FROM
(
select kd_op_beli_tunai,
tanggal,
count(kd_op_beli_tunai) as quantity_id_sold
from t_pembelian_tunai
group by tanggal,kd_op_beli_tunai
)bt
INNER JOIN
(
select kd_op_beli_tunai, sum(harga_satuan * jumlah) as total_sold
from t_rinci_beli_tunai
group by kd_op_beli_tunai
)rbt on bt.kd_op_beli_tunai = rbt.kd_op_beli_tunai
ORDER by bt.tanggal
使用平均值而不是计数。从计数(bt.kd_op_beli_tunai)?avg(bt.kd_op_beli_tunai)是否在1号答复前关闭?请提供
t pembelian_tunai
和t rinci_beli_tunai
表格中的一些样本数据?
select bt.tanggal as date_sold, count(bt.kd_op_beli_tunai) as quantity_id_sold, sum(rbt.harga_satuan * rbt.jumlah) as total_sold
from t_pembelian_tunai as bt, t_rinci_beli_tunai as rbt
where bt.kd_op_beli_tunai = rbt.kd_op_beli_tunai
GROUP by tanggal
ORDER by tanggal DESC
SELECT bt.tanggal as date_sold,bt.quantity_id_sold,rbt.total_sold
FROM
(
select kd_op_beli_tunai,
tanggal,
count(kd_op_beli_tunai) as quantity_id_sold
from t_pembelian_tunai
group by tanggal,kd_op_beli_tunai
)bt
INNER JOIN
(
select kd_op_beli_tunai, sum(harga_satuan * jumlah) as total_sold
from t_rinci_beli_tunai
group by kd_op_beli_tunai
)rbt on bt.kd_op_beli_tunai = rbt.kd_op_beli_tunai
ORDER by bt.tanggal