Mysql SQL中的CASE语句给出了不正确的值

在sql代码中运行此部分时，我的值异常。SQL语法方面，这一切都好吗

select
  COUNT(CASE WHEN bt.idBillingStatus = 2  
    THEN 1
        ELSE NULL END)           AS successfulbillinghits,
  SUM(CASE WHEN  bt.idBillingStatus = 2 
    THEN price
      ELSE 0.0 END)  
                  AS old_revenue    
from table

总的疑问是这样的。成功计费的结果应等于时间计费

SELECT
  cs.idCustomerSubscription,
  cs.msisdn,
  pro.name                       AS promoterName,
  c.name                         AS ClubName,
  c.idClub                       AS ClubID,
  o.name                        AS operatorName,
  o.idOperator                   AS OperatorID,
  co.name                        AS country,
 -- cu.customerSince               AS CustomerSince,
  cs.subscribeddate              AS subscribeddate,
 -- cs.subscriptionNotificationSent AS SubNotificationSent,
 -- cs.eventId                     AS EventId,
  cs.unsubscribeddate           AS unsubscribeddate,
  cs.firstBillingDate            AS FirstBillingDate,
  cs.lastBilledDate              As LastBilledDate,
  cs.lastAttemptDate             AS LastAttemptDate,
  -- smp.code                       AS packageName,
  -- o.mfactor                      AS mmfactor,
  -- cs.idSubscriptionSource        AS SubscriptionChannel,
  -- cs.idUnsubscribeSource         AS UnsubscriptionChannel,
  -- DATE(bt.creationDate)          AS BillingCreationDate,
  -- bt.price                       AS pricePerBilling,
  -- cs.lastRetryDate               As LastRetryDate,
  -- cs.lastRenewalDate             AS LastRenewalDate,
  -- cs.isActive                    AS ActiveStatus,
  -- COUNT(bt.idBillingTransaction) AS BillingAttempts,
  curr.idcurreny_symbol          AS CurrencyID,
  curr.symbol                    AS currency,
  date(bt.creationDate)          AS BillingDate,
  cs.lastBilledAmount            As LastBilledAmount,
  cs.timesbilled,
  price,
 --  sum(price),
  -- revenueShareAmountLocal,
  -- o.mfactor,
  -- count(IFF (bt.idBillingStatus = 2,1,0)) as otherversion,

  count(CASE WHEN bt.idBillingStatus = 2  
    THEN 1
        ELSE 0 END)           AS successfulbillinghits,
  SUM(CASE WHEN  bt.idBillingStatus = 2 
    THEN price 
      ELSE 0.0 END)  
                  AS old_revenue   

FROM
  customersubscription cs
  LEFT JOIN
  billing_transaction bt
    ON CONVERT(cs.msisdn USING latin1) = bt.msisdn 
       AND cs.idClub = bt.idClub
       AND bt.creationDate BETWEEN cs.SubscribedDate AND COALESCE(cs.UnsubscribedDate, now())

  INNER JOIN customer cu ON (cs.idCustomer = cu.idcustomer)
  INNER JOIN operator o ON (o.idoperator = cu.idoperator)
  INNER JOIN country co ON (co.`idCountry` = o.idCountry)
  INNER JOIN curreny_symbol curr ON (curr.idcurreny_symbol = co.idCurrencySymbol)
  LEFT JOIN Promoter pro ON cs.idPromoter = pro.id  
  INNER JOIN club_operator_relationships cor ON cor.clubId = cs.idClub 
  INNER JOIN club c ON c.idClub = cs.idClub
  -- INNER JOIN operator op ON op.idOperator = cu.idOperator


WHERE
-- (cs.timesbilled > 0 and cs.subscribeddate < '2016-09-01 00:00:00' ) 
cs.subscribeddate between '2017-04-20 00:00:00' and '2017-04-21 00:00:00'
  AND cs.idClub IN (39) 
GROUP BY idCustomerSubscription, ClubName, operatorName, promoterName

Successfulbillinghits比结果中的TimeBilled大得多，而不是COUNTuse SUM，因为count也会计算空白或空值

  select
  SUM(CASE WHEN bt.idBillingStatus = 2  
    THEN 1
        ELSE 0 END)           AS successfulbillinghits,
  SUM(CASE WHEN  bt.idBillingStatus = 2 
    THEN price
      ELSE 0.0 END)  
                  AS old_revenue    
from table

您可以将WHERE子句与这些聚合函数一起使用，而不是使用CASE，例如：

SELECT COUNT(*) as `successfulbillinghits`, SUM(price) as `old_revenue`
FROM table bt
WHERE bt.idBillingStatus = 2;

---

查询中的“bt”表示什么？描述异常-您得到的值是预期值的整数倍吗？如果是这样，那么几乎可以肯定的是，问题出在未显示的受约束联接上us@hammy你能添加当前和预期的输出吗？更新了同样的问题。那么，忽略逻辑和所有，案例陈述本身是好的吗？有别的办法吗？是的，案例陈述很好。有很多选择。您可以使用内部查询，分别计算2个值，然后在外部查询中获取它们query@hammy-目前，关键的细节，如你正在尝试做什么，你期望的结果是什么，你收到的结果是什么，等等，只在你的头脑中。当我们不知道目标是什么，也不知道当前代码为什么达不到目标时，您怎么能期望我们提出备选方案？请尝试：-按cs.idCustomerSubscription分组，cs.msisdn，pro.name，c.name，c.idClub，o.name，o.I运营商，公司名称，cs.subscribeddate，cs.unsubscribeddate，cs.firstBillingDate，cs.lastBilledDate，cs.lastAttemptDate，curr.idcurreny_symbol，curr.symbol，datebt.creationDate，cs.lastBilledAmount，cs.TimeBilled，PriceThreaded。我没打通。这是分组的问题吗？