Mysql 如何在酒店预订系统中准确查询未预订房间？

我正在用php和mysql做酒店预订系统的项目 我创建了下面的rooms表

room_no| roo_id | room_type
 D1     |  1     | Deluxe
 R1     |  2     | AC
 R2     |  3     | Non Ac
 C1     |  4     | Cottage

这张表是关于房间的，代表酒店的总房间数

这是客户预订台

customer_id | Cust_name | email | Address | room_type | room_no| cost|check_in | check_out
1 | satyawan |ss@gmail.com| xy | AC       |  R1    |5000 | 2012-12-26|2012-12-30
2 |satyawan  |   lahu@gmail.com|unr  |  Non A/C | R6 |            20002012-01-01|2012-12-07
3 |satyawan  |   lahu@gmail.com|unr  |  Non A/C | R8 |            2013-01-01  |2013-01-10
4 |satyawan  |   lahu@gmail.com|unr  |  Non A/C | R9 |            2013-01-10 |2013-01-16
5 |satyawan  |   lahu@gmail.com|unr  |  Non A/C | R6 |            2013-01-01 |2013-01-20

我已经对这两个表的联接启动了查询，以获取未预订房间的排序数据。查询如下

SELECT *
FROM rooms 
LEFT JOIN customer_booking  
ON customer_booking.room_no = rooms.room_no
WHERE customer_booking.client_id IS NULL
OR (customer_booking.check_out >= 2013-01-01
AND customer_booking.check_in >= 2013-01-10)
OR (customer_booking.check_out <= 2013-01-01
AND customer_booking.check_out <= 2013-01-10)

选择*
从房间
左加入客户预订
客户预订时。房间号=房间号
其中customer\u booking.client\u id为空
或（客户预订。退房>=2013-01-01
和客户（预订。入住>=2013-01-10）
或者（customer\u booking.check\u out也许您正在寻找
不在

SELECT * FROM rooms AS r WHERE r.room_no NOT IN (
   SELECT cb.room_no FROM customer_booking AS cb WHERE your_checkin_constraints); 

尝试使用此查询。如果最后一个字段
room\u customer\u id
为0，则room是免费的，否则将显示预订此房间的客户id

SELECT rooms.*,COALESCE(customer_booking.customer_id,0) room_customer_id
FROM rooms 
LEFT JOIN customer_booking  ON 
   (customer_booking.room_no = rooms.room_no)
   and 
   (
      ('2013-01-01' between customer_booking.check_in and customer_booking.check_out)
      or 
      ('2013-01-10' between customer_booking.check_in and customer_booking.check_out)
      or 
      (customer_booking.check_in between '2013-01-01' and '2013-01-10')
    )

选择r.room，如果r.room\u no为空，则选择“可用”
否则“不可用”结束
从r房间
左加入客户预订cb
在cb.room\U no=r.room\U no上
还有，像这样试试，你会得到d间没有预订的房间

SELECT * FROM room r WHERE 
 not exists (
   SELECT cb.room_no FROM customer_booking cb where cb.room_no=r.room_no);

子选择与实际的左连接和空（或非空）测试相比，在性能上非常糟糕@DRapp:通常但不总是。非常接近……他正在寻找第1-10个占用范围，在in/out之间添加2013-01-10，您应该会很好。@DRapp我已修复此查询。谢谢
SELECT * FROM room r WHERE 
 not exists (
   SELECT cb.room_no FROM customer_booking cb where cb.room_no=r.room_no);