MySql查询不同条件

我有这个桌子结构

yymm | orderid | itemid | price | qty | status
2011 | 123456  | ABC    | 100   | 1   | completed
2011 | 123456  | DEF    | 200   | 1   | completed
2010 | 112233  | ABC    | 100   | 1   | cancelled
2010 | 112233  | DEF    | 200   | 1   | cancelled

我想知道完成和取消了多少不同的订单 我提出了这个问题，但这并不清楚

select date,
COUNT(IF(status = 'completed', 1, NULL)) AS completed,
COUNT(IF(status = 'cancelled', 1, NULL)) AS cancelled
from my_table
GROUP BY date
order by date

如何计算不同的顺序

预期的结果是

date | completed | cancelled
2011 | 1         | 0
2010 | 0         | 1

谢谢

使用countdistinct：

我更喜欢case而不是if，因为case是条件逻辑的SQL标准。

或者

select count(distinct order_id), date
from my_table
where status in ('completed','cancelled')
GROUP BY date
order by date

---

谢谢，我被错误地放在了不同的内部，比如COUNTIFstatus='completed'，不同的orderid，NULL

select count(distinct order_id), date
from my_table
where status in ('completed','cancelled')
GROUP BY date
order by date