MySQL总和和大小写是否可能在DISTINCTROW上？

我有一个疑问：

SELECT
    p.name,
    COUNT(DISTINCT t.keyTask) AS totalTasksCount,
    SUM(DISTINCT CASE WHEN t.keyPriority = 24 AND (t.keyState = 16 OR t.keyState = 17) THEN 1 ELSE 0 END) AS highPriorityTasksCount,
    SUM(DISTINCT CASE WHEN t.keyState = 16 OR t.keyState = 17 THEN 1 ELSE 0 END) AS activesTasksCount,
    SUM(DISTINCT t.estimatedDuration) AS estimatedDuration,
    SUM(TIMESTAMPDIFF(SECOND,wp.start,wp.end)) * 1000 AS workedDuration
FROM projects_projects p
LEFT JOIN projects_tasks t
    ON p.keyProject = t.keyProject
LEFT JOIN projects_workPeriods wp
    ON wp.keyTask = t.keyTask
LEFT JOIN common_organizations o
    ON o.keyOrganization = p.keyOrganization
LEFT JOIN common_users uc
    ON uc.keyUser = p.keyUserCreator
LEFT JOIN common_users uu
    ON uu.keyUser = p.keyUserUpdater
GROUP BY
    p.keyProject
ORDER BY
    highPriorityTasksCount DESC,
    activesTasksCount DESC,
    p.updated DESC,
    p.name;

但是结果字段

highpriorityTaskScont

和

ActiveStaskScont

返回0或1，这在该查询中是正常的。我想知道是否有任何方法可以使

DISTINCTROW

在没有子查询的情况下对这些字段的行而不是案例结果值进行操作

当前结果：

p.name,
totalTasksCount,
highPriorityTasksCount,
activesTasksCount,
estimatedDuration,
workedDuration

'Project 1',  '4', '1', '1',  '14400000',  '15300000'
'Project 2', '48', '1', '1',  '84600000', '503100000'
'Project 3',  '6', '1', '1', '108000000',        NULL
'Project 4',  '4', '1', '1',  '25200000',  '30600000'
'Project 5',  '5', '1', '1', '226800000',  '39600000'
'Project 6',  '2', '0', '1',        NULL,  '10800000'
'Project 7',  '9', '0', '1',        NULL,  '36900000'

'Project 1',  '4', '1', '1',  '14400000',  '15300000'
'Project 2', '48','20', '2',  '84600000', '503100000'
'Project 3',  '6', '1', '1', '108000000',        NULL
'Project 4',  '4', '4', '2',  '25200000',  '30600000'
'Project 5',  '5', '5', '1', '226800000',  '39600000'
'Project 6',  '2', '0', '1',        NULL,  '10800000'
'Project 7',  '9', '0', '1',        NULL,  '36900000'

预期结果：

p.name,
totalTasksCount,
highPriorityTasksCount,
activesTasksCount,
estimatedDuration,
workedDuration

'Project 1',  '4', '1', '1',  '14400000',  '15300000'
'Project 2', '48', '1', '1',  '84600000', '503100000'
'Project 3',  '6', '1', '1', '108000000',        NULL
'Project 4',  '4', '1', '1',  '25200000',  '30600000'
'Project 5',  '5', '1', '1', '226800000',  '39600000'
'Project 6',  '2', '0', '1',        NULL,  '10800000'
'Project 7',  '9', '0', '1',        NULL,  '36900000'

'Project 1',  '4', '1', '1',  '14400000',  '15300000'
'Project 2', '48','20', '2',  '84600000', '503100000'
'Project 3',  '6', '1', '1', '108000000',        NULL
'Project 4',  '4', '4', '2',  '25200000',  '30600000'
'Project 5',  '5', '5', '1', '226800000',  '39600000'
'Project 6',  '2', '0', '1',        NULL,  '10800000'
'Project 7',  '9', '0', '1',        NULL,  '36900000'

编辑：

p.name,
totalTasksCount,
highPriorityTasksCount,
activesTasksCount,
estimatedDuration,
workedDuration

'Project 1',  '4', '1', '1',  '14400000',  '15300000'
'Project 2', '48', '1', '1',  '84600000', '503100000'
'Project 3',  '6', '1', '1', '108000000',        NULL
'Project 4',  '4', '1', '1',  '25200000',  '30600000'
'Project 5',  '5', '1', '1', '226800000',  '39600000'
'Project 6',  '2', '0', '1',        NULL,  '10800000'
'Project 7',  '9', '0', '1',        NULL,  '36900000'

'Project 1',  '4', '1', '1',  '14400000',  '15300000'
'Project 2', '48','20', '2',  '84600000', '503100000'
'Project 3',  '6', '1', '1', '108000000',        NULL
'Project 4',  '4', '4', '2',  '25200000',  '30600000'
'Project 5',  '5', '5', '1', '226800000',  '39600000'
'Project 6',  '2', '0', '1',        NULL,  '10800000'
'Project 7',  '9', '0', '1',        NULL,  '36900000'

使用子查询修改查询由于没有办法，请提供有关优化的帮助，此项功能正在运行：

SELECT
    p.name,
    COUNT(DISTINCT t.keyTask) AS totalTasksCount,
    /* OLD SUM(DISTINCT CASE WHEN t.keyPriority = 24 AND (t.keyState = 16 OR t.keyState = 17) THEN 1 ELSE 0 END) AS highPriorityTasksCount, */
    (
        SELECT
    SUM(CASE WHEN st.keyPriority = 24 AND (st.keyState = 16 OR st.keyState = 17) THEN 1 ELSE 0 END)
    FROM projects_tasks st
    WHERE
    st.keyProject = p.keyProject
) AS highPriorityTasksCount,
    /* OLD SUM(DISTINCT CASE WHEN t.keyState = 16 OR t.keyState = 17 THEN 1 ELSE 0 END) AS activesTasksCount, */
    (
        SELECT
    SUM(CASE WHEN st.keyState = 16 OR st.keyState = 17 THEN 1 ELSE 0 END)
    FROM projects_tasks st
    WHERE
    st.keyProject = p.keyProject
) AS activesTasksCount,
    SUM(t.estimatedDuration) AS estimatedDuration,
    SUM(TIMESTAMPDIFF(SECOND,wp.start,wp.end)) * 1000 AS workedDuration
FROM projects_projects p
LEFT JOIN projects_tasks t
    ON p.keyProject = t.keyProject
LEFT JOIN projects_workPeriods wp
    ON wp.keyTask = t.keyTask
LEFT JOIN common_organizations o
    ON o.keyOrganization = p.keyOrganization
LEFT JOIN common_users uc
    ON uc.keyUser = p.keyUserCreator
LEFT JOIN common_users uu
    ON uu.keyUser = p.keyUserUpdater
GROUP BY
    p.keyProject
ORDER BY
    highPriorityTasksCount DESC,
    activesTasksCount DESC,
    p.updated DESC,
    p.name;

没有子查询

---

不，您必须使用子查询，或者MySQL有一些我不知道的地方。

您能为两个结果集中的列添加标签吗？当前结果和预期结果有什么区别results@SashiKant第三列和第四列有不同的值。我添加了标签。。。不在列的顶部，因为名称太长，顺序相同。